Answer:
v = 3200 m/s
Explanation:
As we know that the frequency of the sound wave is given as
wavelength of the sound wave is given as
so now we have
so we will have
C) for every action there is an equal and opposite reaction.
Answer:
a. V = 0.015 m³
b. ζ = 195.58 kg acetone / hr
Explanation:
a.
Assume ideal gas behavior can use the equation
n₁ = 1.1 bar / 1.013 bar = 1.085 * 1m³( 273 k / 478 k ) * ( 1 kmol / 274 m³)
n₁ = 0.0276 kmol
Pacetone = 0.1 bar ⇒ y₁ = 0.1 bar / 1.1 bar
y₁ = 0.09090
Pacetone = 0.379 bar ⇒ y₃ = 0.379 bar / 40 bar
y₃ = 9.475 x10 ⁻³
n₁ * y₁ = n₃ * y₃ ⇒ 0.0276 * ( 1 - 0.09090) = n₃ * ( 1 - 9.475 x 10⁻³)
n₃ = 0.0253 kmol
n₁ = n₂ + n₃ ⇒ n₂ = 0.0276 - 0.0253 = 2.30 x 10 ⁻³ kmol
Volume condesed
V = 0.0253 kmol * 22.4 m³ * ( 283 / 273 ) * ( 1013 bar / 40 bar )
V = 0.015 m³
b.
To calculate the rate vaporized
ζ = 20.0 m³ / hr *( 0.0276 / 0.014 kg * m³ ) *( 0.09090 kmol a / kmol ) * ( 5808 kg a / kmol a )
ζ = 195.58 kg acetone / hr
Answer:
the answer is kinetic energy
A droplet of pure mercury has a density of 13.6 g/cm3. What is the density of a sample of pure mercury that is 10 times as large as the droplet?
Answer: In this case the density will remain constant for both droplets. The reason being that volume will not change the density of the material. The only way of changing it is by changing its state. If you increase the volume then the mass will also increase. Leaving the density the same.
I hope it helps, Regards.