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2 years ago

Mr. Barcena reached a top speed of 5m/s in 2 seconds from rest, what was his average acceleration including units?

Physics

1 answer:

sashaice [31]2 years ago

4 0

Answer:

Explanation:

The equation for acceleration is

$a=\frac{v_f-v_0}{t}$ where vf is the final velocity and v0 is the initial velocity. Filling in:

$a=\frac{5-0}{2}$ so

a = 2.5 m/s/s

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a flag of mass 2.5 kg is supported by a single rope. A strong horizontal wind exerts a force of 12 N on the flag. Calculate the

tatuchka [14]

The free-body diagram of the forces acting on the flag is in the picture in attachment.

We have: the weight, downward, with magnitude
$W=mg = (2.5 kg)(9.81 m/s^2)=24.5 N$
the force of the wind F, acting horizontally, with intensity
$F=12 N$
and the tension T of the rope. To write the conditions of equilibrium, we must decompose T on both x- and y-axis (x-axis is taken horizontally whil y-axis is taken vertically):
$T \cos \alpha -F=0$
$T \sin \alpha -W=$
By dividing the second equation by the first one, we get
$\tan \alpha = \frac{W}{F}= \frac{24.5 N}{12 N}=2.04$
From which we find
$\alpha = 63.8 ^{\circ}$
which is the angle of the rope with respect to the horizontal.

By replacing this value into the first equation, we can also find the tension of the rope:
$T= \frac{F}{\cos \alpha}= \frac{12 N}{\cos 63.8^{\circ}}=27.2 N$

7 0

3 years ago

Which statement is true of cooling down after physical activity? A cool-down is a period of semistrenuous activity after physica

Xelga [282]

The statement that is true of cooling down after physical activity is that you should cool down for about 5 to 10 minutes after being physically active.

8 0

3 years ago

Read 2 more answers

im bored and lonely put those two together and youve got me. any guys wanna create a zo.om just for fun. im dyying of boredom.

kipiarov [429]

Answer:

just guys

Explanation:

and if not i need how old you are sorry just trying to be safe

7 0

3 years ago

A family car has a mass of 1400 kg. In an accident it hits a wall and goes from a speed of 27 m/s to a standstill in 1. 5 second

madreJ [45]

The force involved is = 25200 Newton

Given the values in the questions,

Mass = 1400 kg

Speed or velocity of the car = 27 m/s

Time is given = 1.5 seconds

According to the formula of force,

⇒ Force = Mass x Acceleration

⇒ Force = 1400 x Acceleration ----- equation 1

Now to calculate the value of acceleration we will use,

⇒ Acceleration = (Velocity or Speed) / Time

⇒ Acceleration = 27 / 1.5

⇒ Acceleration = 18 m/ $s^{2}$

Putting the value of acceleration in equation 1,

⇒ Force = 1400 x 18

⇒ Force = 25200 Newton

Therefore, the force involved is = 25200 Newton

To learn more about Force,

brainly.com/question/13191643

#SPJ4

8 0

1 year ago

Which form of electromagnetic radiation with a relatively high amount of energy is used to sanitize lab goggles?

Nostrana [21]

Answer:

sorry

Explanation:

i don't know this but when i find the answer i will type here

5 0

3 years ago