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Xelga [282]
2 years ago
10

The base ( foundation ) of building is made wider. Why ?​

Physics
1 answer:
attashe74 [19]2 years ago
7 0

Answer: It is increased to exert the pressure off the bywalls and on large area (brainliest pls)

Explanation: ...

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A 72-kg boy is surfing and catches a wave which gives him an initial speed of 1.6 m/s. He then drops through a height of 1.61 m,
chubhunter [2.5K]

Answer:

2849.98 J

Explanation:

From the question,

Work done by the boy = change Potential energy of the boy + change in kinetic energy of the boy

W = ΔP + ΔK..................... Equation 1

Where W = work done by the boy, ΔP = change in potential energy of the boy, ΔK = Change in kinetic energy of the boy.

But,

ΔP = mgΔh.................... Equation 2

ΔK = 1/2mΔv²................. Equation 3

Where m = mass of the boy, Δh = change in height of the boy, Δv = change in velocity of the boy.

Substitute equation 2 and 3 into equation 1

W = mgΔh+1/2mΔv²................. Equation 4

Given: m = 72 kg, Δh = 1.61 m, Δv = 8.5-1.6 = 6.9 m/s, g = 9.8 m/s²

Substitute into equation 4

W = 72(9.8)(1.61)+1/2(72)(6.9²)

W = 1136.016+1713.96

W = 2849.98 J

8 0
3 years ago
Optical tweezers use light from a laser to move single atoms and molecules around. Suppose the intensity of light from the tweez
katrin [286]

Answer:

a= 4.4×10 m/s^2

Explanation:

pressure P  = E/c

Where, E = 100 W/m^2 intensity of light

c= speed of light  = 3×10^8 m/s

P = 1000/ 3×10^8

P = 3.33×10^(-6) Pa

Force F = P×A

  • P is the pressure and c= speed of light

F = 3.33×10^{-6}×6.65×10(-29)

= 2.22×10^{-6}

acceleration a  = F/m = 2.22×10^{-6}/ 5.10×10^{-27}

a= 4.4×10 m/s^2

4 0
3 years ago
A water wave travels 36 meters in 15 seconds. What is the speed of the wave?
atroni [7]
2.4 meters per second

I hope this helps
5 0
3 years ago
Read 2 more answers
Imagine you are sitting on a surfboard in the ocean, waiting to catch a big wave. When the ocean is still, you are sitting at a
aliina [53]
B. What is the frequency
5 0
2 years ago
(11%) Problem 5: A uniform stationary ladder of length L = 2.7 m and mass M = 11 kg leans against a smooth vertical wall, while
jeka94

Answer:

970.2 N

Explanation:

We are given that

Length of ladder=2.7 m

Mass,M=11 kg

Coefficient of friction=\mu=0.45

\theta=51^{\circ}

Mass of painter=8M

Distance from base=d

We have to find the magnitude of the normal force exerted by the floor on the ladder.

Normal force exerted by floor on the ladder=mg+8mg=9mg

Where g=9.8m/s^2

Normal force exerted by floor on the ladder=9\times 11\times 9.8=970.2N

7 0
3 years ago
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