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Xelga [282]
3 years ago
10

The base ( foundation ) of building is made wider. Why ?​

Physics
1 answer:
attashe74 [19]3 years ago
7 0

Answer: It is increased to exert the pressure off the bywalls and on large area (brainliest pls)

Explanation: ...

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Can someone please help me?
natita [175]

Answer:

1.0 A

Explanation:

8 0
3 years ago
how is the acceleration of a car traveling on an elevated air track related to the angle of elevation
quester [9]
Acceleration is a vector quantity that expresses the rate of change in velocity. Being a vector quantity, then the value has magnitude and direction. If the car exerts a constant net force as it travels, the greater the angle of elevation is, the greater is the decrease in its acceleration. Since the vertical component of is affected by the acceleration due to the gravity, that is why vehicles exert more force to climb a steeper hills. 
5 0
3 years ago
Un montañero de 65kg de masa ha ascendido a la cima del Everest, la montaña más alta del mundo de 8848m de altura sobre el nivel
andrew-mc [135]

Answer:

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

Explanation:

Por la definición de trabajo sabemos que el montañero debió contrarrestar trabajo causado por la gravedad terrestre. Si asumimos que el cambio de la altura es muy pequeño en comparación con el radio del planeta (6371 kilómetros vs. 0,5 kilómetros), entonces podemos considerar que la aceleración gravitacional es constante y la ecuación de trabajo (\Delta W), medido en joules, que reducida a:

\Delta W = m\cdot g\cdot \Delta z (1)

Donde:

m - Masa del montañero, medido en kilogramos.

g - Aceleración gravitacional, medida en metros por segundo al cuadrado.

\Delta z - Distancia vertical de ascenso del montañero, medida en metros.

Si tenemos que m = 65\,kg, g = 9,807\,\frac{m}{s^{2}} y \Delta z = 500\,m, entonces el trabajo realizado por el montañero para subir es:

\Delta W = (65\,kg)\cdot \left(9,807\,\frac{m}{s^{2}} \right)\cdot (500\,m)

\Delta W = 318727,5\,J

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

7 0
3 years ago
Consider two identical wave pulses on a rope having a fixed end. Suppose the first pulse reaches the end of the rope, is reflect
jek_recluse [69]

Answer:

zero

Explanation:

Consider two identical wave pulses on a rope having a fixed end. Suppose the first pulse reaches the end of the rope, is reflected back, and then meets the second pulse, both waves will be out of phase by π radians. Therefore, they form destructive interference and hence the amplitude of  the resultant pulse would be zero.

4 0
4 years ago
Two long, parallel wires are separated by a distance of 3.20 cm. The force per unit length that each wire exerts on the other is
AURORKA [14]

Answer:

(a)The current in the second wire = 9.43 A

(b) The two current are in the opposite direction.

Explanation:

The force per unit length (F/l) on a current carrying conductor = μ₀I₁I₂/2πr

Making I₂ The subject of the equation,

I₂ = [2πr(F/l)]/μ₀I₁.................... Equation 1

Where I₁ = Current in the first wire, I₂ = current in the second wire, μ₀ = permeability of vacuum, r = distance of separation between the two wires.

<em>Given: F/l = 3.30 × 10⁻⁵ N/m, I₁ = 0.56 A, r = 3.20 cm = 0.032 m.</em>

<em>Constant: </em>μ₀= 4π × 10⁻⁷ Am⁻¹.

Substituting these values into equation 1

I₂ = (2π × 0.032 × <em>3.30 × 10⁻⁵ )/(</em>4π × 10⁻⁷×0.56)

I₂ = (0.032 × 3.3 × 100)/1.12

I₂ = 10.56/1.12

I₂ = 9.43 A

Therefore the current in the second wire = 9.43 A

(b) The two current are in the opposite direction, because the force on each wire repel each other.

7 0
3 years ago
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