Question

A 1000-kg car is moving along a straight road down a 30∘30∘ slope at a constant speed of 20.0m/s20.0m/s. What is the net force acting on the car?

Answer 1

The net force on the car is zero

Explanation:

Let's analyze the situation separately for the direction along the slope and the direction perpendicular to the slope.

For the direction perpendicular to the slope, there are only 2 forces acting on the car:

• The component of the weight perpendicular to the slope, $mgcos \theta$, pointing inside the slope
• The normal reaction N, pointig outside the slope

There is equilibrium in this direction, so the net force in this direction is zero.

Let's now analyze the direction parallel to the slope. We have two forces:

• The component of hte weight parallel to the slope, $mgsin \theta$, pointing down along the slope
• The force of friction $F_f$, acting up along the slope

We are told that the car moves in this direction at a constant speed: this means that its acceleration is zero,

$a=0$

and therefore, according to Newton's second law,

$F=ma$

This means that the net force is zero:

$F=0$

Learn more about slopes and friction:

brainly.com/question/5884009

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