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Furkat [3]
3 years ago
12

What are 5 metals used as either pure substances or alloys

Physics
1 answer:
Natali5045456 [20]3 years ago
6 0
You might see the word alloy described as a "mixture of metals", but that's a little bit misleading because some alloys contain only one metal and it's mixed in with other substances that are nonmetals (cast iron, for example, is an alloy made of just one metal, iron, mixed with one nonmetal, carbon). The best way to think of an alloy is as a material that's made up of at least two different chemical elements, one of which is a metal. The most important metallic component of an alloy (often representing 90 percent or more of the material) is called the main metal, the parent metal, or the base metal. The other components of an alloy (which are called alloying agents) can be either metals or nonmetals and they're present in much smaller quantities (sometimes less than 1 percent of the total). Although an alloy can sometimes be a compound (the elements it's made from are chemically bonded together), it's usually a solid solution (atoms of the elements are simply intermixed, like salt mixed with water).
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A water bottle is dropped from a plane and accelerates because of gravity. What distance did it fall during 3 seconds?
exis [7]
It’d fall 29.4m or 96.46ft

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4 0
2 years ago
Suppose a car travels 108 km at a speed of 30.0 m/s, and uses 1.90 gallons of gasoline. Only 30% of the gasoline goes into usefu
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686.11 N

1.7733 gallons

Explanation:

\eta = Efficiency = 30%

V = Volume of gasoline

E = Energy content of gasoline = 1.3\times 10^8\ J/gal

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s = Displacement = 108000 m

v = Velocity

Work done is given by

W=F\times s\\\Rightarrow F=\frac{W}{s}\\\Rightarrow F=\frac{VE\eta}{s}\\\Rightarrow F=\frac{1.9\times 0.3\times 1.3\times 10^8}{108000}\\\Rightarrow F=686.11\ N

The force required to keep the car moving at a constant speed is 686.11 N

Here the force is directly proportional to speed

\\\Rightarrow F=v

\\\Rightarrow \frac{F_1}{v_1}=\frac{F_2}{v_2}\\\Rightarrow F_2=\frac{F_1\times v_2}{v_1}\\\Rightarrow F_2=\frac{686.11\times 28}{30}\\\Rightarrow F_2=640.36\ N

W=F\times s\\\Rightarrow 0.3\times 1.3\times 10^8\times V=640.36\times 108000\\\Rightarrow V=\frac{640.36\times 108000}{0.3\times 1.3\times 10^8}\\\Rightarrow V=1.7733\ gal

The gallons that will be used is 1.7733 gallons

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3 years ago
A 7.00-kg bowling ball from a 2.00-m shelf. Just before hitting the floor, what will be it’s kinetic energy?
san4es73 [151]

I'm not sure of the numbers sense I dont have a calculator right now. The formula is 1/2*M*V^2.

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