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harkovskaia [24]
3 years ago
14

Qué método utilizaría para separar los componentes de una mezcla de: limaduras de hierro, azufre en polvo y piedras?

Chemistry
1 answer:
Pachacha [2.7K]3 years ago
8 0

Answer:

Traducción por favor

Explanation:

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g Tibet (altitude above sea level is 29,028 ft) has an atmospheric pressure of 240. mm Hg. Calculate the boiling point of water
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<u>Answer:</u> The boiling point of water in Tibet is 69.9°C

<u>Explanation:</u>

To calculate the boiling point of water in Tibet, we use the Clausius-Clayperon equation, which is:

\ln(\frac{P_2}{P_1})=\frac{\Delta H}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

P_1 = initial pressure which is the pressure at normal boiling point = 1 atm = 760 mmHg      (Conversion factor:  1 atm = 760 mmHg)

P_2 = final pressure = 240. mmHg

\Delta H_{vap} = Heat of vaporization = 40.7 kJ/mol = 40700 J/mol     (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature or normal boiling point of water = 100^oC=[100+273]K=373K

T_2 = final temperature = ?

Putting values in above equation, we get:

\ln(\frac{240}{760})=\frac{40700J/mol}{8.314J/mol.K}[\frac{1}{373}-\frac{1}{T_2}]\\\\-1.153=4895.36[\frac{T_2-373}{373T_2}]\\\\T_2=342.9K

Converting the temperature from kelvins to degree Celsius, by using the conversion factor:

T(K)=T(^oC)+273

342.9=T(^oC)+273\\T(^oC)=(342.9-273)=69.9^oC

Hence, the boiling point of water in Tibet is 69.9°C

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