Question

Peroxyacylnitrate (PAN) is one of the components

Answer 1

C – 19,9%, H – 2,2%, N – 11,6%, O – x%

$M=120\frac{g}{mol}$

1 percentage

The entire molecule is 100% and all the components of the compound add up to 100%.

100% - 19,9% - 2,5% - 11,6% = 66,1%

The compound contains 66,1% oxygen.

2 molar masses

$M_{C}=12,01\frac{g}{mol}$

$M_{H}=1,008\frac{g}{mol}$

$M_{O}=15,999\frac{g}{mol}$

$M_{N}=14,007\frac{g}{mol}$

3 masses

The compound has a molar mass of 120g/mol. So one molecule weighs 120 g. To find out how much the percentage of a component weighs, you have to calculate it using the molar mass.

carbon

19,8% of 120g

$m=120g*0,198\\m=23,76g$

One molecule contains 23,76g of carbon.

hydrogen

2,5% of 120g

$m=120g*0,025\\m=3g$

One molecule contains 3g of hydrogen.

oxygen

66,1% of 120g

$m=120g*0,661\\m=79,32g$

One molecule contains 79,32g of oxygen.

nitrogen

11,6% of 120g

$m=120g*0,0,116\\m=13,92g$

One molecule contains 13,92g of nitrogen.

4 amount of substance

carbon

$n=\frac{23,76g}{12,01\frac{g}{mol} }\\n=1,98mol$

The compound contains about 2 moles of carbon.

hydrogen

$n=\frac{3g}{1\frac{g}{mol} }\\n=3mol$

The compound contains about 3 moles of hydrogen.

oxygen

$n=\frac{79,32g}{15,999\frac{g}{mol} }\\n=4,96mol$

The compound contains about 5 moles of oxygen.

nitrogen

$n=\frac{13,92g}{14,007\frac{g}{mol} }\\n=0,99mol$

The compound contains about 1 moles of nitrogen.

5. molecular formula

The formula results from the ratio of the amounts of substance.

$n_{C} :n_{H} :n_{O} :n_{N} =2:3:5:1\\C_{2}H_{3}NO_{5}$