Answer:
C. Speed
Explanation:
Density differences in different materials are able to change the speed of a wave.
- Wave speed is dependent on the frequency and wavelength of a wave.
- As a wave travels from one medium to another, the speed of the wave changes.
- Speed of a wave is medium dependent.
- The denser a medium, the slower the speed of waves will be be.
- A less dense medium will have waves traveling through faster.
H₂ + CO₂ ⇄ CO + H₂O
1 mol H₂ - 1 mol H₂O
x mol H₂ - 30.6 mol H₂O
x=30.6*1/1=30.6 mol (<span>theoretically)</span>
Explanation:
The IUPAC system of nomenclature aims to ensure
that every organic compound has a unique, unambiguous name.that the IUPAC name of any compound conveys the structure of that compound to a person familiar with the system.
One way of checking whether the name you have given to an alkane is reasonable is to count the number of carbon atoms implied by the chosen name. For example, if you named a compound 3‑ethyl-4‑methylheptane, you have indicated that the compound contains a total of 10 carbon atoms—seven carbon atoms in the main chain, two carbon atoms in an ethyl group, and one carbon atom in a methyl group. If you were to check the given structure and find 11 carbon atoms, you would know that you had made a mistake. Perhaps the name you should have written was 3‑ethyl-4,4‑dimethylheptane!
Answer:
The percent yield of NaCl is 78.7 %
Explanation:
CuCl₂ + 2NaNO₃ → Cu(NO₃)₂ + 2NaCl
If the NaNO₃ is determined to be in excess, the limiting reagent is the chloride. We convert the mass to moles:
31 g . 1mol / 134.45g = 0.230 moles
Ratio is 1:2, so we can make a rule of three to determine the theoretical yield
1 mol of copper (II) chloride reacts to produce 2 moles of sodium chloride
Then, 0.230 moles of CuCl₂ will react to produce (0.230 .2) /1 ) = 0.461 moles of NaCl → we convert the moles to mass → 0.461 mol . 58.45 g / 1mol = 26.9 g
To find percent yield we do → (Yield produced / Theoretical yield) . 100
(21.2 g / 26.9 g) . 100 = 78.7 %
Answer:
Explanation:
From the question we are told that:
Initial Volume 
Final Volume 
Generally the equation for one ounce is mathematically given by
Therefore
