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natita [175]
2 years ago
5

A sample of oxygen occupied 626 mL when the pressure increased to 874.27 mm Hg. At constant temperature, what volume did the gas

initially occupy when the pressure was 771.75 mm Hg?
Chemistry
1 answer:
Usimov [2.4K]2 years ago
4 0

Answer:

709 (With sig figs)

Explanation:

Pressure(1) * volume(1) = Pressure(2) * volume(2)

771.75 mm Hg * unknown = 874.27 mm Hg * 626 mL

771.75 mm Hg * unknown = 547,293.02 mm Hg*mL

   Divide both sides by 771.75 mm Hg

Unknown = 709 (With sig figs)....709.158432 (without sig figs)

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\quad \huge \quad \quad \boxed{ \tt \:Answer }

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Explanation:

Hello!

In this case, since the reaction between sulfur and oxygen is:

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Whereas there is a 1/2:8 mole ratio between oxygen and SO3, and we can compute the produced grams of product as shown below:

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Best regards!

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3 years ago
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