1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
I am Lyosha [343]
3 years ago
10

A student prepares a 15.0 % salt solution in a 250.00 mL volumetric flask. What is the mass of salt in the solution?

Chemistry
1 answer:
Yuri [45]3 years ago
4 0

Answer:

44.1 g

Explanation:

15 % = mass salt/mass salt +mass water

.15( mass water) +.15 mass salt =mass salt

.15(250g water) +.15mass salt = mass salt

37.5=.85 mass salt

44.1

You might be interested in
What is a unifying principle that explains a body of
padilas [110]
The answer to this question is theory
3 0
3 years ago
I REALLY NEED HELP can someone help me please I’ll make you brainliest ! :)
Nikitich [7]

Answer:

C

Explanation:

All thing in option c is flammable

5 0
2 years ago
Read 2 more answers
Gaseous butane, CH3(CH2)2CH, reacts with gaseous oxygen gas, O2, to produce gaseous carbon dioxide, CO2, and gaseous water, H2O.
weeeeeb [17]

Answer:

Percentage yield of carbon dioxide is 49.9%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CH3(CH2)2CH3 + 13O2 —> 8CO2 + 10H2O

OR

2C4H10 + 13O2 —> 8CO2 + 10H2O

Next, we shall determine the masses of butane and oxygen that reacted and the mass of carbon dioxide produced from the balanced equation. This is illustrated below:

Molar mass of butane C4H10 = (12×4) + (10×1)

= 48 + 10

= 58 g/mol

Mass of C4H10 from the balanced equation = 2 × 58 = 116 g

Molar mass of O2 = 16 × 2 = 32 g/mol

Mass of O2 from the balanced equation = 13 × 32 = 416 g

Molar mass of CO2 = 12 + (16×2)

= 12 + 32

= 44 g/mol

Mass of CO2 from the balanced equation = 8 × 44 = 352 g

Summary:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen to produce 352 g of carbon dioxide.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen.

Therefore, 34.29 g of butane will react with = (34.29 × 416) / 116 = 122.97 g of oxygen.

From the calculation made above, we can see clearly that only 122.97 g out of 165.7 g of oxygen reacted completely with 34.29 g of butane. Therefore, butane is the limiting reactant and oxygen is the excess reactant.

Next, we shall determine the theoretical yield of carbon dioxide.

In this case, we shall use the limiting reactant because it will give the maximum yield of carbon dioxide as all of it is used up in the reaction.

The limiting reactant is butane and the theoretical yield of carbon dioxide can be obtained as follow:

From the balanced equation above,

116 g of butane reacted to produce 352 g of carbon dioxide.

Therefore, 34.29 g of butane will react to produce = (34.29 × 352) / 116 = 104.05 g of carbon dioxide.

Therefore, the theoretical yield of carbon dioxide is 104.05 g

Finally, we shall determine the percentage yield of carbon dioxide as follow:

Actual yield of carbon dioxide = 51.9 g

Theoretical yield of carbon dioxide = 104.05 g

Percentage yield of carbon dioxide =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield of carbon dioxide = 51.9 / 104.05 × 100

Percentage yield of carbon dioxide = 49.9%

7 0
3 years ago
What is the molarity of a 0.65L solution containing 63 grams of ? The molar mass of NaCl is 58.44 g/mol
ad-work [718]

Explanation:

The molarity of a solution is defined like the number of moles of solute per liters of solution.

molarity = moles of solute/(volume of solution in L)

We know the volume of solution in L.

volume of solution = 0.65 L

To go from the mass of our solute in grams to moles we have to use its molar mass.

mass of NaCl = 63 g

molar mass of NaCl = 58.44 g/mol

moles of NaCl = 63 g * 1 mol/(58.44 g)

moles of NaCl = 1.078 moles

Finally we can find the molarity of the solution

molarity = moles of NaCl/(volume of solution)

molarity = 1.078 moles/(0.65 L)

molarity = 1.66 M

Answer: the molarity of the solution is 1.66 M.

7 0
1 year ago
Someone help me with this ASAP! ^_^
kaheart [24]
I think it’s C sry if I’m wrong
4 0
3 years ago
Read 2 more answers
Other questions:
  • What is the mass of 1.0 x 10-3 mole of Zn? 3.9 x 1022 0.065 0.000015
    14·2 answers
  • Which type of reaction is caused by particle accelerators?
    9·2 answers
  • Single-crystal sapphire has a melting point of aorund 2323K what is the melting point in degrees Celsius?
    14·1 answer
  • How many moles of sulfur are needed to react completely with 1.2 mol of O2?
    9·1 answer
  • What should you do with a rag that has been used to wipe up spilled gasoline? a)Place it in the bilge. b)Hang it over the gunwal
    8·1 answer
  • Sodium+cloride what is the moleculat mass​
    13·2 answers
  • What is the power of yet is
    13·1 answer
  • The half-life of C-14 is 5470 years. If a particular archaeological sample has one-quarter of its original radioactivity remaini
    11·1 answer
  • In the event that a chemical gets in your eye while in the lab, you would use the eyewash station. In your at-home lab, however,
    7·1 answer
  • Determining what it is you want to know:
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!