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I am Lyosha [343]
3 years ago
10

A student prepares a 15.0 % salt solution in a 250.00 mL volumetric flask. What is the mass of salt in the solution?

Chemistry
1 answer:
Yuri [45]3 years ago
4 0

Answer:

44.1 g

Explanation:

15 % = mass salt/mass salt +mass water

.15( mass water) +.15 mass salt =mass salt

.15(250g water) +.15mass salt = mass salt

37.5=.85 mass salt

44.1

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A baseball player hits a ball. Which is the best description of the energy of the ball as it flies over the pitcher’s head?
Elan Coil [88]

The right option is; b. mechanical

Mechanical energy is the best description of the energy of the ball as it flies over the pitcher’s head.

Mechanical energy is the energy that an object acquires due to its position or due to its motion. From the question, the baseball player has chemical potential energy (stored as food) which is transformed into work. As the baseball player hits the ball, there is energy exchange in which the ball acquires energy to perform its work. The energy obtained by the ball upon which work is done is called mechanical energy.


3 0
3 years ago
Read 2 more answers
3) How many moles of solute are dissolved in 1.5 L of a 0.80 M solution? * 10 points
Mrrafil [7]

Answer:

1.2

Explanation:

Molarity = moles/volume

to find the moles, you must multiply both sides by volume

so, take 1.5 L * 0.80 M

this equals 1.2 :)

7 0
2 years ago
Compare and contrast absolute and relative dating
svet-max [94.6K]
There is no question
7 0
2 years ago
What was the plum pudding atomic model
postnew [5]
Thomson's atomic model is a theory about the atomic structure proposed in 1904 by Thomson, who discovered the electron in 1897, a few years before the discovery of the proton and the neutron.

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3 0
2 years ago
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A metal, M, forms an oxide having the formula MO2 containing 59.93% metal by mass. Determine the atomic weight in g/mole of the
Damm [24]

Answer:

See solution.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to set up the formula for the calculation of the by-mass percentage of the metal:

\%  M=\frac{m_M}{m_M+2*m_O}*100 \%\\\\59.93\%  =\frac{m_M}{m_M+32.00}*100 \%

Thus, we solve for the molar mass of the metal to obtain:

59.93\% (m_M+32.00) =m_M*100 \%\\\\m_M*59.93\% +1917.76\% =m_M*100 \%\\\\m_M=47.86g/mol

For the subsequent problems, we proceed as follows:

a.

4.00gO_2*\frac{1molO_2}{32.00gO_2}=0.125molO_2

b.

0.400molH_2S*\frac{2molH}{1molH_2S}*\frac{6.022x10^{23}atomsH}{1molH}=4.82x10^{23}atomsH

c.

0.235gNH_3*\frac{1molNH_3}{17.03gNH_3} *\frac{3molH}{1molNH_3}*\frac{6.022x10^{23}atomsH}{1molH}=2.49x10^{22}atomsH

Regards!

7 0
2 years ago
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