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erastovalidia [21]
4 years ago
10

A 6.32-l football is filled with air at 1.90 atm. the volume of the football is reduced to 3.49 l what is the pressure of the ba

ll?
Chemistry
1 answer:
arsen [322]4 years ago
5 0
You can use the formula P1V1= P2V2

(1.90)(6.32L)=P1(3.49 L).

Solve for the unknown.

P1= 3.44 atm
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What is the solubility of argon (in units of grams per liter) in water at 25 °C, when the Ar gas over the solution has a partial
beks73 [17]

Answer:

0.02405 g/L is the solubility of argon  in water at 25 °C.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{Ar}=K_H\times p_{gas}

where,

K_H = Henry's constant = 1.40\times 10^{-3}mol/L.atm

p_{Ar} = partial pressure of carbonated drink = 0.51atm

Putting values in above equation, we get:

C_{Ar}=1.40\times 10^{-3}mol/L.atm\times 0.430 atm\\\\C_{Ar}=6.02\times 10^{-4}mol/L

Molar mass of argon = 39.95 g/mol

Solubility of the argon gas :

6.02\times 10^{-4}mol/L\times 39.95 g/mol=0.02405 g/L

0.02405 g/L is the solubility of argon  in water at 25 °C.

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4 years ago
What is the answer???
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The bowl has more volume, the bearing has more volume. The mass is bigger for the bearing because it is heavier than the bowl. It is made of metal and the weight of it is greater than the bowl.(the body shape).
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4 years ago
If Hershey and Chase had used radioactive oxygen in their experiments instead of phosphorus and sulfur, what results would they
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3 years ago
Calculate how many grams of the product form when 16.7 g of calcium metal completely reacts. Assume that there is more than enou
swat32

39.96 g product form when 16.7 g of calcium metal completely reacts.

<h3>What is the stoichiometric process?</h3>

Stoichiometry is a section of chemistry that involves using relationships between reactants and/or products in a chemical reaction to determine desired quantitative data.

Equation:

Ca(s) + Cl_2(g) → CaCl_2(s)

In this case, for the undergoing reaction, we can compute the grams of the formed calcium chloride by noticing the 1:1 molar ratio between calcium and it (stoichiometric coefficients) and using their molar mass of 40 g/mol and 111 g/mol by using the following stoichiometric process:

m_{ca_C_l_2}= 16.7 g Ca x \frac{1 mol \;of \;Ca}{40g Ca} x \frac{1 mol \;of \;CaCl_2}{1 mol \;Ca} x \frac{111g of \;CaCl_2}{1 mol \;CaCl_2}

m_{ca_C_l_2} = 39.96 g

Hence, 39.96 g product form when 16.7 g of calcium metal completely reacts.

Learn more about the stoichiometric process here:

brainly.com/question/15047541

#SPJ1

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2 years ago
Discovered electrons have fixed amounts of energy and orbit the nucleus similar to planets? A. John dalton B. J.J. Thomson C. Er
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I think is letter c thanks




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