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4 years ago

Does the structure below exhibit geometric isomerism? ch3 tally1 ch3― c ―ch═ch―ch3 tally1 ch3

Chemistry

1 answer:

lubasha [3.4K]4 years ago

6 0

Answer:
YES! The given compound exhibit Geometrical Isomerism.

Explanation:
In Geometrical Isomerism or Cis-Trans Isomerism, isomers possess same molecular formula, same structural formula with a double bond and with a only difference in the arrangement of atoms or group of atoms about the double bond in three dimensional space.
4,4-dimethylpent-2-ene (given problem) has two groups about the double bond i.e. Methyl (CH₃-) and tertiary Butyl [(CH₃)₃-C-]. In cis configuration both groups are at same side of the double bond, while in trans configuration both groups are located opposite to each other as shown below;

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Perform the following calculations, then round off each answer to the proper number of significant figures: 1210.0 g + 157.22 g

ohaa [14]

Answer:- 1337 g

Solution:- For mathematical operations we use PEMDAS. P stands for parenthesis off, E stands for exponents, M stands for multiplication, D stands for division, A stands for addition and S stands for subtraction. All the mathematical operations are done in this sequence.

What we have given in the problem is, 1210.0 g + 157.22 g - 30. g

Here we have addition and subtraction. As per the law, we will do addition first. In addition and subtraction we go with least number of decimal places.

1210.0 has one decimal place where as 157.22 has two decimal places, since the first number has least decimal places(one decimal place), the answer should also have only one decimal place.

1210.0 g + 157.22 g = 1367.2 g

Now, we will do subtraction. 30. does not have any decimal place and so on subtraction the final answer must not have any decimal places.

1367.2 g - 30. g = 1337 g

So, the final answer is 1337 g.

5 0

3 years ago

Which of the following molecules nonpolar?

kap26 [50]

Answer:

CHC13

Explanation:

4 0

4 years ago

Benzene is 92.3% carbon and 7.7% hydrogen. In anexperiment,

Marysya12 [62]

Answer:

The molecular formula of benzene = $C_{6}H_{6}$

Explanation:

$Moles =\frac {Given\ mass}{Molar\ mass}$

% of C = 92.3

Molar mass of C = 12.0107 g/mol

% moles of C = $\frac{92.3}{12.0107}$ = 7.6848

% of H = 7.7

Molar mass of H = 1.00784 g/mol

% moles of H = $\frac{7.7}{1.00784}$ = 7.6401

Taking the simplest ratio for C and H as:

7.6848 : 7.6401

= 1 : 1

The empirical formula is = $CH$

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Mass from the Empirical formula = 12+ 1 = 13 g/mol

Molar mass = 78.0 g/mol

So,

Molecular mass = n × Empirical mass

78.0 = n × 13

⇒ n ≅ 6

<u>The molecular formula of benzene = $C_{6}H_{6}$ </u>

7 0

4 years ago

If an atom has 5 electrons in the 3rd orbital, what "time" on a clock would the 5th

Fiesta28 [93]

Answer:

The 5th electron can be placed at either the 12, 9, 3, or 6 O'clock locations

Explanation:

The steps to writing the Lewis symbol of an atom includes;

1) The number of valence electrons for the element is determined based on the position of the element on the periodic table which arranges the elements in groups depending on their valency electrons

2) Place dots one at a time, at the top bottom , left and right of the chemical symbol of the element, with a maximum of 4 dots, in the order of your choice

However, ensure that elements with less than four valence electrons have the electrons placed at the above described locations, with a maximum of one in each location

3) Where the valence electrons are more than 4, the extra electrons are again shared in the four locations to form a pair with the previous four dots

Therefore, whereby the element has 5 valence electrons as in the question, the fifth electron can either be at the top, left, right or bottom locations, corresponding to a 12, 9, 3, or 6 O'clock locations.

7 0

3 years ago

A baker touches a pie right after taking it out of the oven. Which statement best explains why the pie feels hot?

Oksana_A [137]

The answer is letter B, because according to the Second Law of Thermodynamics heat can only move from a hotter body to one of colder temperature. So that's your answer: as the molecules in the pie move faster (are hotter) than the ones in the skin, heat is transfered from the pie to the skin.

6 0

3 years ago

Read 2 more answers