Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer:
The area of the circle is 379.94 mm²
Step-by-step explanation:
To solve this problem we need to use the area formula of a circle:
a = area
r = radius = 11 mm
π = 3.14
a = π * r²
we replace with the known values
a = 3.14 * (11 mm)²
a = 3.14 * 121 mm²
a = 379.94 mm²
Round to the nearest tenth
a = 379.94 mm² = 379.9 mm²
The area of the circle is 379.9 mm²
U need to find the square root by long division.
So the answer would be 2.2
Answer:
1. 1050
2. 200 x 5.25= C
3. 155 students
Step-by-step explanation:
1. 5.25 x 200= 1,050
2. you multiply 200 x 5.25 the c is the unknown cost
3. To find how many tickets were purchased you need to divide 813.75 by 5.25
