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grigory [225]
2 years ago
10

The efficiency of a canot engine is more when the temperature of the sink is increased by 50%

Physics
1 answer:
timama [110]2 years ago
4 0

The efficiency of a carnot engine is more when the temperature of the sink is increased by 50% is 33.33%

<h3>What is Efficiency?</h3>

The efficiency is defined as the work done by the engine divided by the heat supplied.

Work done is the difference between the heat supplied and heat rejected.

So, efficiency η = 1 - T₁/T₂

Where T₁ is the lower temperature and T₂ is the higher temperature.

The temperature of the sink is increased by 50%. If the lower temperature is T₁, then the higher temperature will be 1.50T₁

Substitute the value into the expression , we get

η = 1 - T₁ / 1.5T₁ x 100 %

η = 33.33 %

Thus, the efficiency of the carnot engine is 33.33 %

Learn more about efficiency.

brainly.com/question/13828557

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\Rightarrow I_1\omega_1=I_2\omega_2\\\Rightarrow \dfrac{4.5\times 15^2}{2}\cdot 4\pi=(\dfrac{4.5\times 15^2}{2}+\dfrac{2.8\times 8^2}{2})\omega_2\\\\\Rightarrow \omega _2=\dfrac{4\pi }{1+\dfrac{2.8}{4.5}\times (\dfrac{8}{15})^2}=\dfrac{4\pi}{1+0.1769}=0.849\times 4\pi

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