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grigory [225]
2 years ago
10

The efficiency of a canot engine is more when the temperature of the sink is increased by 50%

Physics
1 answer:
timama [110]2 years ago
4 0

The efficiency of a carnot engine is more when the temperature of the sink is increased by 50% is 33.33%

<h3>What is Efficiency?</h3>

The efficiency is defined as the work done by the engine divided by the heat supplied.

Work done is the difference between the heat supplied and heat rejected.

So, efficiency η = 1 - T₁/T₂

Where T₁ is the lower temperature and T₂ is the higher temperature.

The temperature of the sink is increased by 50%. If the lower temperature is T₁, then the higher temperature will be 1.50T₁

Substitute the value into the expression , we get

η = 1 - T₁ / 1.5T₁ x 100 %

η = 33.33 %

Thus, the efficiency of the carnot engine is 33.33 %

Learn more about efficiency.

brainly.com/question/13828557

#SPJ1

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We have v_f=-v_i, so that

-2v_i=at\implies-2\left(8\,\dfrac{\mathrm m}{\mathrm s}\right)=\left(-2\,\dfrac{\mathrm m}{\mathrm s^2}\right)t\implies t=8\,\mathrm s

(b) The speed of the ball at the start and at the end of the roll are the same 8 m/s, so the average speed is also 8 m/s.

(c) The ball's average velocity is 0. Average velocity is given by \dfrac{v_i+v_f}2, and we know that v_f=-v_i.

(d) The position of the ball x_f at time t is given by

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Take the starting position to be the origin, x_i=0. Then after 6 seconds,

x_f=\left(8\,\dfrac{\mathrm m}{\mathrm s}\right)(6\,\mathrm s)+\dfrac12\left(-2\,\dfrac{\mathrm m}{\mathrm s^2}\right)(6\,\mathrm s)^2=42\,\mathrm m

so the ball is 42 m away from where it started.

We're not asked to say in which direction it's moving at this point, but just out of curiosity we can determine that too:

x_f-x_i=\dfrac{v_i+v_f}2t\implies42\,\mathrm m=\dfrac{8\,\frac{\mathrm m}{\mathrm s}+v_f}2(6\,\mathrm s)\implies v_f=6\,\dfrac{\mathrm m}{\mathrm s}

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8 0
3 years ago
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<h3><u>Answer;</u></h3>

<u>  = 55.2 Coulombs </u>

<h3><u>Explanation</u>;</h3>

We can determine Charge using the formula

Q =It, where Q is the amount of charge in Coulombs, I is the current in amperes and t is the time in seconds.

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Note: Although the video is not provided in this question, it is not needed to answer the question.

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