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2 years ago

Help me people( ◜‿◝ )♡

Physics

2 answers:

almond37 [142]2 years ago

6 0

Answer:

Explanation:

the temperature at and above which vapor of the substance cannot be liquefied, no matter how much pressure is applied.

Elodia [21]2 years ago

3 0

Answer:

<h3>Surface tension of a liquid at critical temperature is</h3><h2><em>Zero</em></h2>

Explanation:

At the critical temperature, the surface tension decreases with the increase of temperature, hence reaching a value of zero.

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an empty propane tank dropped from a hot air balloon hits the ground with a speed of 143.8 m/s. from what height was the tank re

vodomira [7]

What you know:
Vi=0m/s
Vf=143.8m/s
A=-9.8m/s
d=???
Use the equation Vf^2=Vi^2+2A(d)
Rearrange to isolate d: d=Vf^2/2A
d=(143.8)^2/2(-9.8)
d=20678.4/-19.6
d=-1055m
The tank was released from a height of 1055m

8 0

3 years ago

Please I really need help on these

blagie [28]

Answer:

3, 4, 2

Explanation:

I can't see the final ones.

4 0

2 years ago

Argument changes meaning because of an ambiguous word or phrase.

Virty [35]

I think the answer is D

7 0

3 years ago

The energy required to ionize magnesium is 738 kj/mol. What minimum frequency of light is required to ionize magnesium

Cerrena [4.2K]

Answer:

The minimum frequency required to ionize the photon is 111.31 × $10^{37}$ Hertz

Given:

Energy = 378 $\frac{kJ}{mol}$

To find:

Minimum frequency of light required to ionize magnesium = ?

Formula used:

The energy of photon of light is given by,

E = h v

Where E = Energy of magnesium

h = planks constant

v = minimum frequency of photon

Solution:

The energy of photon of light is given by,

E = h v

Where E = Energy of magnesium

h = planks constant

v = minimum frequency of photon

738 × $10^{3}$ = 6.63 × $10^{-34}$ × v

v = 111.31 × $10^{37}$ Hertz

The minimum frequency required to ionize the photon is 111.31 × $10^{37}$ Hertz

7 0

3 years ago

Read 2 more answers

A small economy car (low mass) and a limousine (high mass) are pushed from rest across a parking lot, equal distances with equal

Studentka2010 [4]

Answer:

The car that receives more kinetic energy is the small economy car.

Explanation:

K.E = 0.5*mv²

Where;

K.E is the kinetic Energy

M is the mass of an object

V is the velocity of the moving object

But F = m(v/t), from Newton's second law of motion

If equal forces were applied to the two cars, then the velocity of each car will be calculated as follows.

v = (Ft/m)

v² = (Ft/m)²

Substitute in the value of v² into Kinetic energy equation

K.E = 0.5*mv²

K.E = 0.5*m(Ft/m)² = (0.5*F²t²)/m

Also assuming equal distance, equal force and assuming equal time for both cars.

The above equation will reduce to, K.E = k/m

Where k = 0.5*F²t², which is equal in both cars.

Thus, Kinetic energy will depend only on the mass of each car.

From the above expression, Kinetic Energy received by each car is inversely proportional to the mass of the car.

A small economy car (low mass) will receive more kinetic energy while a limousine (high mass) car will receive less kinetic energy.

Therefore, the car that receives more kinetic energy is the small economy car.

6 0

3 years ago

Help me people( ◜‿◝ )♡​

Help me people( ◜‿◝ )♡