Answer:
Magnitude of the magnetic field inside the solenoid near its centre is 1.293 x 10⁻³ T
Explanation:
Given;
number of turns of solenoid, N = 269 turn
length of the solenoid, L = 102 cm = 1.02 m
radius of the solenoid, r = 2.3 cm = 0.023 m
current in the solenoid, I = 3.9 A
Magnitude of the magnetic field inside the solenoid near its centre is calculated as;

Where;
μ₀ is permeability of free space = 4π x 10⁻⁷ m/A

Therefore, magnitude of the magnetic field inside the solenoid near its centre is 1.293 x 10⁻³ T
That can be considered alive.
This question involves the concepts of th magnetic field and current.
The magnetic field created by the current at the house is "6.75 x 10⁻⁷ T".
<h3>Magnetic Field</h3>
The magnetic field created by a current carrying wire can be given by the following formula:

where,
- B = magnetic field = ?
= permeabiliy of free space =4π x 10⁻⁷- I = current = 152 A
- r = distance = 45 m

B = 6.75 x 10⁻⁷ T
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Answer: 
Explanation:
Given
Wavelength of light 
Screen is
away
Distance between two adjacent bright fringe is 
When same experiment done in water, wavelength reduce to 
So, the distance between the two adjacent bright fringe is 
Keeping other factor same, distance becomes
