Can someone help me with this please

The resistor potential is constant and the inductor emf increases. The resistor potential is constant and the inductor emf decre

maks197457 [2]

The question is incomplete, the complete question is

When an RL circuit is connected to a battery, what happens to the potential difference across the resistor and the emf across the inductor?

The resistor potential is constant and the inductor emf increases.

The resistor potential is constant and the inductor emf decreases.

The resistor potential is constant and the inductor emf is constant.

The resistor potential decreases and the inductor emf is constant.

The resistor potential decreases and the inductor emf increases.

The resistor potential decreases and the inductor emf decreases.

The resistor potential increases and the inductor emf increases.

The resistor potential increases and the inductor emf is constant.

The resistor potential increases and the inductor emf decreases.

Answer:

The resistor potential increases and the inductor emf decreases.

Explanation:

From Kirchoff's rule, we can easily see that voltage across the inductor decreases steadily in a RL circuit until it finally gets to zero when the circuit is connected to a battery. A graph of the drop in potential across the inductor is attached for more clarity.

The drop shown in figure (b) in the image attached is the drop in potential across the inductor when an RL circuit is connected to a battery.

6 0

4 years ago

Water is flowing through a 45° reducing pipe bend at a rate of 200 gpm and exits into the atmosphere (P2 = 0 psig). The inlet to

Nataliya [291]

Answer:

F1=177.88 Newtons

Explanation:

Let's start with the Bernoulli's equation:

$P_{1} + \frac{1}{2}\beta V_{1} ^{2} + \beta gh_{1} =P_{2} + \frac{1}{2}\beta V_{2} ^{2} + \beta gh_{2}$

Where:

P is pressure, V is Velocity, g is gravity, h is height and β is density (for water β=1000 kg/m3); at the points 1 and 2 respectively.

From the Bernoulli's equation and assuming that h is constant and P2 is zero (from the data), we have:

$P_{1} + \frac{1}{2}\beta V_{1} ^{2} = \frac{1}{2}\beta V_{2} ^{2}$

As we know, P1 must be equal to $\frac{F_{1} }{A_{1}}$ , so, replacing P1 in the equation, we have:

$P_{1} = \frac{F_{1}}{A_{1}} = \frac{1}{2}\beta(V_{2} ^{2} - V_{1} ^{2})$

And

$F_{1} = {A_{1}} ( \frac{1}{2}\beta(V_{2} ^{2} - V_{1} ^{2}))$

Now, let's find the velocity to replace the values on the expression:

We can express the flow in function of velocity and area as $Q = V A$ , where Q is flow, V is velocity and A is area. As the same, we can write this: $Q_{1} = V_{1} A_{1}\\Q_{2} = V_{2} A_{2}$ . In the last two equations, let's clear Velocities.

$V_{1} = \frac{Q_{1}}{A_{1}}\\V_{2} = \frac{Q_{2}}{A_{2}}$

and replacing V1 and V2 on the last equation resulting from Bernoulli's (the one that has the force on it):

$F_{1} = {A_{1}} ( \frac{1}{2}\beta((\frac{Q_{2}}{A_{2}})^{2} - (\frac{Q_{1}}{A_{1}})^{2}))$

First, we have to consider that from a mass balance, the flow is the same, so Q1=Q2, what changes, is the velocity. Knowing this, let's write the areas, diameters, density and flow on International Units System (S.I.), because the exercise is asking us the answer in Newtons.

$D_{1}=1.5 inches=0.0381 mts\\D_{2}=1 inches=0.0254 mts\\A_{1}=\frac{\pi D_{1}^{2} }{4}=0.00114mts^{2}\\A_{2}=\frac{\pi D_{2}^{2} }{4}=0.000507mts^{2}\\\beta=1000 kgs/m^{3}\\Q=200gpm=0.01mts^{3}/seg$

Replacing the respective values in this last expression, we obtain:

F1 = 177.88 N

3 0

3 years ago

Pierre is a 375 kg great white with an average speed of 3 m/s. When Pierre spots a seal, he increases his velocity to 7 m/s. Aft

tangare [24]

Answer:

1890J

Explanation:

375+45 = 420kg (total mass)

kinetic energy = 1/2 × mass × velocity²

1/2 × 420 × 3² = 1890J

5 0

3 years ago

Marcus attends a night program at an observatory to learn more about the solar system. He learns that the solar system contains

Lesechka [4]

Answer: D meteoroid

Explanation:

Meteoroid is the smallest among them. It is a tiny asteroid or the broken-off crumb of comets and sometimes planets. It ranges in size from a grain of sand to boulders 3 feet (1 meter) wide. When meteoroids collide with a planet's atmosphere, they become meteors. If those meteors survive the atmosphere and hit the planet's surface, their remains are called meteorites

8 0

3 years ago

A football player pushes against another player trying to block him from moving any farther down the field. Which term best desc

Juli2301 [7.4K]

Answer:

its a negative work, not a negative force

Explanation:

I took the quiz first i put negative force i got it wrong

then when i put negative work it was right

Hope it help:)♥︎ plz mark me as brainliest

8 0

4 years ago