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Sergio [31]
3 years ago
9

Simplify (3 1/7)^7 Apex

Mathematics
2 answers:
Anton [14]3 years ago
7 0

Answer:

(3\frac{1}{7})^7 in simplified form is 3028.81

Step-by-step explanation:

We have to simplify

(3\frac{1}{7})^7

Converting mixed fraction into improper fraction

(\frac{22}{7})^7

we know (a/b)^n = a^n/b^n

Applying

\frac{(22)^7}{(7)^7} \\\frac{2494357888}{823543} \\3028.81

So (3\frac{1}{7})^7 in simplified form is 3028.81

MariettaO [177]3 years ago
7 0

Answer:  (3\ \frac{1}{7})^7=3,028.81

Step-by-step explanation:

We can convert the mixed number inside the parentheses into a fraction.

We need to multiply the denominator of the fractional part by the whole number and add the numerator to the product. This will be the new numerator. The new denominator of the fraction will be the same original denominator of the fractional part. Then:

(3\ \frac{1}{7})^7=(\frac{(3*7)+1}{7})^7=(\frac{21+1}{7})^7=(\frac{22}{7} )^7

Remember that:

(\frac{a}{b})^n=\frac{a^n}{b^n}

Then we get:

\frac{22^7}{7^7}=\frac{2,494,357,888}{823,643}=3,028.81

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Answer:

The value of the test statistic is t = 1.97

Step-by-step explanation:

The null hypothesis is:

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The alternate hypotesis is:

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In which X is the sample mean, \mu is the null hypothesis value, \sigma is the standard deviation and n is the size of the sample.

In this problem:

X = 251.6, \mu = 250, \sigma = 5.4, n = 44

So

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In a clinical test with 2161 subjects, 1214 showed improvement from the treatment. Find the margin of error for the 95% confiden
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Answer:

The margin of error for the 95% confidence interval used to estimate the population proportion is of 0.0209.

Step-by-step explanation:

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In a clinical test with 2161 subjects, 1214 showed improvement from the treatment.

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Answer:

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