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Alika [10]
2 years ago
13

What is the Substance that is oxidized in 2K+ S > K2S

Chemistry
2 answers:
ludmilkaskok [199]2 years ago
8 0

Answer :]

This is an oxidation-reduction (redox) reaction:

S0 + 2 e- → S-II (reduction)

2 K0 - 2 e- → 2 KI (oxidation)

S is an oxidizing agent, K is a reducing agent.

kherson [118]2 years ago
5 0

Answer:

<u>K</u>

Explanation:

Here, in this reaction 2 moles of potassium react with 1 mole of sulfur to form 1 mole of potassium sulfide.

Let's compare the electronic configurations of both elements :

⇒ K = {2, 8, 8, 1}

⇒ K can attain noble gas configuration by losing one electron

⇒ K exists as : <u>K⁺</u>

<u />

⇒ S = {2, 8, 6}

⇒ S can attain noble gas configuration by the addition of 2 electrons

⇒ S exists as <u>S²⁻</u>

Now, we know that will lose protons when oxidized. Hence, here the substance which is oxidized is <u>K</u>

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