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1 year ago

Summer homework, need help

Mathematics

2 answers:

Nataliya [291]1 year ago

6 0

Answer:

5,2,3

Step-by-step explanation:

I don't really know what to say. Im in midd school and I saw this before.................

Marrrta [24]1 year ago

5 0

Answer:
5,2,3

Hope this helps

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10. If ABCD is a kite, DB=48 in. and CE=7 in. find DC. *

Dmitry_Shevchenko [17]

Answer:

25 in.

Step-by-step explanation:

DEC is a right triangle. <DEC is a right angle.

(DE)² + (EC)² = (DC)²

DE = ½DB = ½(48 in.) = 24 in.

(24 in.)² + (7 in.)² = (DC)²

576 in.² + 49 in.² = (DC)²

(DC)² = 625 in.²

DC = 25 in.

3 0

2 years ago

The heights of two cylinders are in the ratio of 5:3 and their volume are in the ratio 20:27. then the ratio of their radius is.

vichka [17]

Answer:

2 : 3

Step-by-step explanation:

Let,

Radius of cylinder 1 = R

Radius of cylinder 2 = r

Now,

We know that

Volume of cylinder = πr²h

=> πR²h/πr²h' = 20/27

=> R² × 5/r² × 3 = 20/27

=> R²/r² = 20/27 × 3/5

=> R²/r² = 4/9

=> R/r = √(4/9)

=> R/r = 2/3

=> R : r = 2 : 3

4 0

2 years ago

Read 2 more answers

Jonah is purchasing a car that is on sale for 15% off. He knows the function that represents the sale price of his car is c(p) =

nika2105 [10]

The answer is b, f[c(p)]=0.9265p.

f[c(p)]=f(0.85p)=1.09(0.85p)=0.9265p

7 0

3 years ago

Please help me understand this

Anastaziya [24]

Answer:

$x=11$

Step-by-step explanation:

So we have the equation:

$\frac{-2-2x}{3} =-8$

First, multiply both sides by 3. This cancels out the denominator:

$3(\frac{-2-2x}{3} )=3(-8)$

The left side cancels. Multiply the right:

$(-2-2x)=-24$

Add 2 to both sides. The 2s on the left cancel:

$(-2-2x)+2=(-24)+2\\-2x=-22$

Divide both sides by -2. The -2 on the left cancel.

$(-2x)/-2=(-22)/-2\\x=11$

Therefore, the answer is 11.

8 0

3 years ago

Read 2 more answers

Review the work showing the first few steps in writing a partial fraction decomposition.

Amanda [17]

Answer:

$A = 2$

$B = -1$

$C = -9$

Step-by-step explanation:

Given

$2x\² + 15x + 19 = Ax\² + 8Ax + 16A + Bx + 4B + C$

Required

Find A, B and C

Rearrange the expression

$2x\² + 15x + 19 = Ax\² + 8Ax + 16A + Bx + 4B + C$

$2x\² + 15x + 19 = Ax\² + 8Ax + Bx + 16A + 4B + C$

To do this, we simply compare the expressions on both sides of the equation.

So, we have:

$Ax\² = 2x\²$ --- (1)

$8Ax + Bx = 15x$ --- (2)

$16A + 4B + C = 19$ --- (3)

Divide both sides by x² in (1)

$Ax\² = 2x\²$

$A = 2$

Divide both sides by x in (2)

$8Ax + Bx = 15x$

$8A + B = 15$

Substitute 2 for A.

$8*2 + B = 15$

$16+ B = 15$

Make B the subject

$B = 15 - 16$

$B = -1$

Substitute 2 for A and -1 for B in (3)

$16A + 4B + C = 19$

$16*2 + 4*-1 + C = 19$

$32 - 4 + C = 19$

$28 + C = 19$

Make C the subject

$C = 19 - 28$

$C = -9$

6 0

2 years ago

Read 2 more answers