The Numerator is 1, which is the top. The Denominator is the 8. I like to remember (D)own is the (D)enominator.
There is no hard and fast rule to select the class width. It largely depends on our application.However, one thing that should be kept in mind is that the number of classes should neither to be too low nor too high. So keeping this thing in mind, the class width is select.
The range of the data is = Maximum- Minimum = 96 - 11 = 85
10 classes will be most suited for this data.
The class width for each data can be calculated as:
Class Width = Range / Number of Classes = 85/10 = 8.5
Class width is always rounded to nearest next integer. So the class width will be 9 in this case.
So, the best value of class width or interval width for the given data will be 9.
Answer:
The required ratio is 38 : 7
Step-by-step explanation:
Given,
304 calories burned in 56 minutes,
That is, the number of calories burnt in 56 minutes = 304
So, the ratio of the calories burnt and time in minutes = 
∵ HCF(304, 56) = 8,
Thus, the ratio of price of photos and number of photos = 
= 
Answer:
I am pretty sure the answer is 3. hope this helps
Perpendicular to the line y = 5x - 9
m= -1/5
the line passing through the point (1, 4):
4=-1/5*1+q
q= 21/5
the equation is:
y= -1/5x +21/5
or
x+5y-21=0
