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2 years ago

what is our best hypothesis for why all the planets in our solar system orbit in the same direction as the sun rotates?

Physics

1 answer:

avanturin [10]2 years ago

8 0

The conservation of angular momentum is the reason that (nearly) all of them rotate in the same direction.

<h3>Which explanation for the solar system is more plausible?</h3>

The nebular hypothesis is regarded as the most widely accepted theory of planetary creation. According to this theory, a massive molecular cloud several light-years across gravitationally collapsed to create the Solar System 4.6 billion years ago.

<h3>What is the solar system's foundational theory?</h3>

The nebular hypothesis states that our solar system arose at the same period as our Sun. The nebular hypothesis proposes that a spinning cloud of dust called a nebula, composed primarily of light elements, flattened into a protoplanetary disk and developed into a solar system made up of a star with orbiting planets .

To know more about solar system orbit visit:-

brainly.com/question/14919738

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Relation of Kilometre and mile

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1km = o.621371 mile

Explanation:

1.609 kilometers equal 1 mile. The kilometer is a unit of measurement, as is the mille. However, a mile is longer than a kilometer.

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3 years ago

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4 years ago

In a velocity-time graph what is represented by the slope, or steepness of the graph line.

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3 years ago

A simple model for a person running the 100 m dash is to assume the sprinter runs with constant acceleration until reaching top

Trava [24]

Answer:

He will complete the race in total time of T = 10 s

Explanation:

Total distance moved by the sprinter in 2.14 s is given as

$s = \frac{(v_{in} + v_{f})}{2} time$

$s = \frac{(0 + 11.2)}{2} (2.14)$

$s = 11.98 m$

now the distance remaining to move

$d = 100 - 11.98 = 88 m$

now he will move with uniform maximum speed for the remaining distance

so we will have

$time = \frac{d}{v}$

$time = \frac{88}{11.2} = 7.86 s$

so the total time to complete the race is given as

$T = 7.86 + 2.14 = 10 s$

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3 years ago

The surface of the dock is 6 feet above the water. If you pull the rope in at a rate of 2 ft/sec, how quickly is the boat approa

Oduvanchick [21]

Answer:

The boat is approaching the dock at a rate of <u>2.5 ft/s</u>.

Explanation:

Let the rope length be 'l' at any time 't', the distance of boat from dock be 'b' at any time 't'.

Given:

The height of dock above water (h) = 6 feet

Rate of pull of rope or rate of change of rope is, $\frac{dl}{dt}=2\ ft/s$

As clear from the question, the height is fixed and only the length 'l' and distance 'b' varies with time 't'.

Now, the above situation represents a right angled triangle as shown below.

Using Pythagoras Theorem, we have:

$l^2=h^2+b^2\\\\l^2=6^2+b^2\\\\l^2=36+b^2----------(1)$

Now, differentiating the above equation with time 't', we get:

$2l\frac{dl}{dt}=0+2b\frac{db}{dt}\\\\l\frac{dl}{dt}=b\frac{db}{dt}\\\\\frac{db}{dt}=\frac{l}{b}\frac{dl}{dt}------(2)$

Now, the distance 'b' can be calculated using 'l=10 ft' in equation (1). This gives,

$b^2=10^2-36\\\\b=\sqrt{64}=8\ ft$

Now, substituting all the given values in equation (2) and solve for $\frac{db}{dt}$ . This gives,

$\frac{db}{dt}=\frac{10}{8}\times 2\\\\\frac{db}{dt}=2.5\ ft/s$

Therefore, the boat is approaching the dock at a rate of 2.5 ft/s.

7 0

3 years ago