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maw [93]
4 years ago
13

Accuracy is the correctness of a measurement. true or false.

Physics
2 answers:
Over [174]4 years ago
8 0

Answer:

True

Explanation:

Accuracy indicates how close to the true measurement you actually are.

Let us understand this with an example.

If a rod produced by a manufacturer has a specification of 1 meter length and after measuring it you also get 1 m length then the measurement is highly accurate.

There is another term called precision which is used in the same sense as accuracy called precision but they do not have the same meaning. Precision refers to how close in the measurements you are while taking multiple readings.

mash [69]4 years ago
6 0
It is true i think so 
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The driver of a 1000 kg car traveling at a speed of 16.7 m/s applies the brakes. If the brakes provide a force of - 8000 N to st
RSB [31]

Answer:

Given:

m=1000kg

u= 16.7m/s

v=0m/s

F=8000N

Required:

s=?

Solution:

F=m × a

8000N=1000kg × a

a=8m/s^2

Since it decelerate a= -8m/s^2

v^2 = u^2 + 2as

s=v^2 - u^2 / 2a

s= 0 - (16.7m/s)^2 / 2 × -8m/s^2

s= -278.89/-16

s= 17.43m

The car travels approximately 17.43m before it stops

Please like and follow me

6 0
2 years ago
As a pendulum bob swings back and forth several times, the maximum height it reaches becomes less and less.
Ymorist [56]

Answer:

A or B

Explanation:

4 0
3 years ago
Mercury’s natural state is where the atoms are close to each other but are still free to pass by each other. In which state(s) c
Georgia [21]

Answer:

Mercury's natural state is where the atoms are close to each other but are still free to pass by each other. In which state(s) could mercury naturally exist?

Liquid is the answer

Explanation:

4 0
2 years ago
Determine the change in electric potential energy of a system of two charged objects when a -2.1-C charged object and a -5.0-C c
elena55 [62]

Answer:

Change in electric potential energy ∆E = 365.72 kJ

Explanation:

Electric potential energy can be defined mathematically as:

E = kq1q2/r ....1

k = coulomb's constant = 9.0×10^9 N m^2/C^2

q1 = charge 1 = -2.1C

q2 = charge 2 = -5.0C

∆r = change in distance between the charges

r1 = 420km = 420000m

r2 = 160km = 160000m

From equation 1

∆E = kq1q2 (1/r2 -1/r1) ......2

Substituting the given values

∆E = 9.0×10^9 × -2.1 ×-5.0(1/160000 - 1/420000)

∆E = 94.5 × 10^9 (3.87 × 10^-6) J

∆E = 365.72 × 10^3 J

∆E = 365.72 kJ

6 0
3 years ago
A 4400 W motor is used to do work. If the motor is used for 200 s, how much work could it do? (Power: P = W/t)
guajiro [1.7K]
So if p=w/t
then 4400=(w)(200)
so you would multiply 4440•200 and get 880,000
3 0
4 years ago
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