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musickatia [10]
3 years ago
6

When the C4 key on a piano keyboard is pressed, a string inside the piano is struck by a hammer and begins vibrating back and fo

rth at approximately 260 cycles per second.
a. What is the frequency in Hertz of the sound wave?
b. What is the wavelength of the wave?
Physics
1 answer:
Anettt [7]3 years ago
8 0

Answer:

Frequency = 260 Hz and wavelength = 1.31 m

Explanation:

Given that,

A hammer begins vibrating back and forth at approximately 260 cycles per second.

(a) The frequency of an object is the number of vibrations per unit time. The frequency of the sound wave is 260 Hz.

(b) The speed of sound in air is 343 m/s. So,

v=f\lambda\\\\\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{343}{260}\\\\\lambda=1.31\ m

Hence, this is the required solution.

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A 1.11 kg piece of aluminum at 78.3 c is put into a glass with 0.210 kg of water at 15.0
ValentinkaMS [17]

M = mass of aluminium = 1.11 kg

c_{a} = specific heat of aluminium = 900

T_{ai} = initial temperature of aluminium = 78.3 c

m = mass of water = 0.210 kg

c_{w} = specific heat of water = 4186

T_{wi} = initial temperature of water = 15 c

T = final equilibrium temperature = ?

using conservation of heat

Heat lost by aluminium = heat gained by water

M c_{a} (T_{ai} - T) = m c_{w} (T - T_{wi} )

(1.11) (900) (78.3 - T) = (0.210) (4186) (T - 15)

T = 48.7 c

7 0
3 years ago
What will be the final temperature if a 4.00 g silver ring at 41.0◦C if it gives off 18.0 J of heat to the surroundings? The spe
Eduardwww [97]

Answer:

Final temperature, T_f=21.85^{\circ}

Explanation:

Given that,

Mass of silver ring, m = 4 g

Initial temperature, T_i=41^{\circ}C

Heat released, Q = -18 J (as heat is released)

Specific heat capacity of silver, c=0.235\ J/g\ C

To find,

Final temperature

Solution,

The expression for the specific heat is given by :

Q=mc\Delta T

Q=mc(T_f-T_i)

T_f=\dfrac{-Q}{mc}+T_i

T_f=\dfrac{-18}{4\times 0.235}+41

T_f=21.85^{\circ}

So, the final temperature of silver is 21.85 degrees Celsius.

5 0
3 years ago
A vinyl record is played by rotating the record so that an approximately circular groove in the vinyl slides under a stylus. Bum
AleksandrR [38]

Answer:

Hits per second=199 hit/s

Explanation:

#Given the angular velocity, \omega=33\frac{1}{3} rev/min , radius of the record r=0.1m and the distance between any two successive bumps on the groove as d=1.75mm.

The linear speed of the record in meters per second is:

v=\omega r=33\frac{1}{3}\times\frac{2\pi}{60}\times 10\times 10^{_2}\\\\=0.3843m/s\\

#From v above, if the bumps are uniformly separated by 1m, then the rate at which they hit the stylus is:

Hits/second=v/d    \ \ \ \ d=1.75mm\\\\=0.3483/0.000175\\\\=199.0385714\approx 199

Hence the bumps hit the stylus at around 199hit/s

8 0
3 years ago
What could result from regular participation in sports and exercise
shusha [124]
Common health issues that can be positively affected, prevented or controlled by exercise.
5 0
3 years ago
two cars start at the same point and drive in a straight line for 5km. At the end of the drive their distances are the same but
Anna11 [10]

A 'displacement' always consists of a magnitude and a direction.  The two cars you just described have displacements with the same magnitude ... 5 km.  But if they didn't both drive in the same direction, then their displacements are different.

Remember:

-- 10 m/s² up and 10 m/s² down are different accelerations

-- 30 mph East and 30 mph West are the same speed but different velocity.

-- 5 km North and 5 km South are the same distance but different displacement.

7 0
3 years ago
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