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Basile [38]
2 years ago
11

How could you improve your boat design to increase the buoyant force without using more clay?

Physics
1 answer:
alukav5142 [94]2 years ago
7 0

Widening the boat or creating a boat with thinner clay walls could result in a greater displacement of water, and increased buoyancy.

<h3>Buoyancy:</h3>

The Greek mathematician and inventor Archimedes discovered the physical law of buoyancy, which states that any body completely or partially submerged in a fluid (gas or liquid) at rest is subject to an upward, or buoyant, force whose magnitude is equal to the weight of the fluid displaced by the body.

The volume of fluid that has been displaced is equal to the volume of an object that is completely submerged in the liquid or to the portion of the volume below the surface for an object that is only partially submerged. The buoyant force's strength is equal to the weight of the fluid that has been dispersed. A body floating in a liquid or gas experiences an analogous buoyant force.

The buoyant force acting on a body floating in a liquid or gas is opposite in direction and of a magnitude equal to the weight of the body; the body neither rises nor falls as a result. For instance, when a ship is launched, it sinks into the ocean until the water it moves is exactly equal to its own weight. The buoyant force continuously equals the weight of the ship and its cargo because when the ship is laden, it descends farther and moves more water.

Learn more about buoyancy here:

brainly.com/question/11884584

#SPJ4

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Answer:

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             P = \frac{F_{1} }{A_{1} } = \frac{F_{2} }{A_{2} }

If we use the subscript 1 for the piston diameter mentor (d = 1.00vm) which is r = 0.05 cm, the force is F1 = 45 lb

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in area of ​​a circules

         A = π r²

we substitute

          F₂ = \frac{r_{2}^2 }{r_{1}^2}  F_{1}

let's calculate

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\\ \rm\longmapsto P.E=mgh

\\ \rm\longmapsto P.E=12(10)(21)

\\ \rm\longmapsto P.E=120(21)

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