The Empirical formula will be C₂H₃O₂ and the Molecular formula would be C₄H₆O₄
<h3>What is Empirical and Molecular Formula ?</h3>
Empirical formula is a formula giving the proportions of the elements present in a compound but not the actual numbers or arrangement of atoms.
Molecular formula is a chemical formula that gives the total number of atoms of each element in each molecule of a substance.
Given ;
- C = 40.6 g
- H = 5.1 g
- O = 54.2 g
Divide each element by its molar weight:
- C = 40.6 / 12 = 3.4
- H = 5.1 / 1 = 5.1
- O = 54.2 / 16 = 3.4
Divide by the smallest Value:
- C = 3.4/3.4 = 1
- H = 5.1/3.4 = 1.5
- O = 3.4/3.4 = 1
Thus, the Empirical formula is C₂H₃O₂
Now, to find the molecular formula ;
[C₂H₃O₂ ]n = molecular formula
where n = molar mass / empirical formula mass
Empirical formula mass = 24 + 3 + 32 = 59
n = 118.084 / 59 = 2
[C₂H₃O₂ ]n = molecular formula
[C₂H₃O₂ ]2 = C₄H₆O₄
Thus, the Molecular formula is C₂H₃O₂
Learn More about Empirical formula here ; brainly.com/question/14044066
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