Viscosity, is a state of matter where it resists flow or may be in thick semifluid form because of friction acting inside the matter.In this case, hot oil room temperature would lessen the viscosity of the oil (animal oil). Thank you for your question. Please don't hesitate to ask in Brainly your queries.
Answer:
6.75 × 10⁻⁸is the value of the equilibrium constant at this temperature.
Explanation:
2H₂O(g) ⇄ 2H₂(g) + O₂(g)
Partial pressure of H₂O = 0.0500 atm
Partial pressure of H₂ = 0.00150 atm
Partial pressure of O₂ = 0.00150 atm
The expression of Kp for the given chemical equation is:
![K_p = \frac{[H_2]^2[O_2]}{H_2O}](https://tex.z-dn.net/?f=K_p%20%3D%20%5Cfrac%7B%5BH_2%5D%5E2%5BO_2%5D%7D%7BH_2O%7D)

6.75 × 10⁻⁸is the value of the equilibrium constant at this temperature
It is usually neutral becase its is close to neutral number 7
Z=35
- The element is bromine
- Sign(Br)
Electronic configuration:-

The answer is C. Here is the work:
<span>Moles=molarity * volume
2.5 * 0.5 = 1.25mols of NaCI
Mm of NaCI= 58.442468/mol
Multiply the moles by the Mm and you get the grams
1.25 * 58.442468 =73.1g
</span>