Answer:
40.7062 °C
Explanation:
Let the initial temperature = x °C
Boiling temperature of water = 100 °C
Using,
Q = m C ×ΔT
Where,
Q is the heat absorbed in the temperature change from x °C to 100 °C.
C gas is the specific heat of the water = 4.184 J/g °C
m is the mass of water
ΔT = (100 - x) °C
Given,
Mass = 2350 g
Q = 5.83 × 10⁵ J
Applying the values as:
Q = m C ×ΔT
5.83 × 10⁵ = 2350 × 4.184 × (100 - x)
<u>x, Initial temperature = 40.7062 °C </u>
This reaction is called the electrolysis of water. The balanced reaction is:
2H2O = 2H2 + O2
We are given the amount of O2 produced from the electrolysis reaction. This will be the starting point of our calculation.
50.00 grams O2 ( 1 mol O2 / 32 grams O2) ( 2 mol H2O / 1 mol O2) ( 18.01 g H2O / 1 mol H2O ) = 56.28 g H2O
In general when you heat up a liquid such as water its volume "increases" as the heat energy causes the water molecules to move leading to more space between molecules causing it to occupy a larger volume.
hope that helps
The mass in grams of butane at standard room temperature is 53.21 grams.
<h3>How can we determine the mass of an organic substance at room temperature?</h3>
The gram of an organic substance at room temperature can be determined by using the ideal gas equation which can be expressed as:
PV = nRT
- Pressure = 1.00 atm
- Volume = 22.4 L
- Rate = 0.0821 atm*L/mol*K
- Temperature = 25° C = 298 k
1 × 22.4 L = n × (0.0821 atm*L/mol*K× 298 K)
n = 22.4/24.4658 moles
n = 0.91556 moles
Recall that:
- number of moles = mass(in grams)/molar mass
mass of butane = 0.91556 moles × 58.12 g/mole
mass of butane = 53.21 grams
Learn more about calculating the mass of an organic substance here:
brainly.com/question/14686462
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