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sergij07 [2.7K]
3 years ago
12

How much energy is released when 22.4g of CH4 is burned?

Chemistry
1 answer:
solniwko [45]3 years ago
5 0

The combustion of methane, CH4, releases 890.4 kJ/mol. That is, when one mole of methane is burned, 890.4 kJ are given off to the surroundings. This means that the products have 890.4 kJ less than the reactants.

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Why do many people have different habits
Lady bird [3.3K]

Answer:

Explanation:

Porque la vida, nuestra vida,  está controlada de manera muy importante por nuestros hábitos, los cuales influyen, de forma, aunque inconsciente en por ejemplo: nuestra salud, productividad, seguridad económica y, como resultado, también en nuestra felicidad. En resumen, en todo y a todos  los que nos rodean.

3 0
3 years ago
Calculate the mass of 29.8 mL of aluminum, which has a density of 2.00 g/mL.
MaRussiya [10]

Answer:

The answer is

<h2>59.6 g </h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

Density of aluminum = 2.00 g/mL

volume = 29.8 mL

The mass is

mass = 2 × 29.8

We have the final answer as

<h3>59.6 g</h3>

Hope this helps you

5 0
3 years ago
Srihari has a torch with him and 2 new batteries. However, the torch requires 3 batteries to work. Is there any way Srihari can
zloy xaker [14]

Answer:

go to the store to buy more batteries

Explanation:

6 0
3 years ago
What volume of 12 M NaOH and 2 M NaOH should be mixed to get 2 litres of 9 M NaOH solution?
Sergio [31]
8/5lit.. of 12M NaOH
2/5lit.. of 2M NaOH
7 0
3 years ago
Which of the following is a salt that will form from the combination of a strong base with a weak acid?
zaharov [31]

Answer:

A. NaHCO₃

Explanation:

NaHCO₃ ⇒ NaOH + H₂CO₃

NaOH is a strong base and H₂CO₃ is a weak acid. Therefore, NaHCO₃ is a salt of a strong base-weak acid reaction. The salt is basic because carbonic acid (H₂CO₃) is a weak acid so it remains undissociated. So, there is a presence of additional OH⁻ ions that makes the solution basic.

Hope that helps.

8 0
3 years ago
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