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ad-work [718]
3 years ago
15

Balance the following reaction in acidic solution:. . Ag(s) + NO3-(aq) -> Ag+(aq) + NO(g)

Chemistry
1 answer:
nekit [7.7K]3 years ago
3 0
The two half-reactions are...
Ag→Ag+
and...
NO3→NO
Let's start by balancing the first half-reaction...
Ag→Ag+
The amounts are already balanced; 1:1. The oxygens are balanced. So all that's left is to balance the charge...
Ag→Ag++e−
Now let's do the other equation... Amounts of nitrogen are balanced, so we first need to balance the oxygens...
NO3→NO
4H++NO3→NO+2H2O
Next, we need to balance charge...
4e−+4H++NO3→NO+2H2O
Now let's go ahead and rewrite each half-reaction after being balanced by themselves...
Ag→Ag++e−
4e−+4H++NO3→NO+2H2O
Now we need to multiply by some factor to get the electrons to cancel out. In this case, that factor is 4, which needs to be applied to the top half-reaction...
4(Ag→Ag++e−)=4Ag→4Ag++4e−
Then we combine this half-reaction with the second one above to get...
4Ag+4H++NO3→4Ag++NO+2H2O
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Answer: 4.32g

Explanation:

MM of H2 = 1 x 2 = 2g/mol

2g of H2 contains 6.02x10^23 atoms.

Therefore Xg of H2 will contain 1.3 x 1024 atoms i.e

Xg of H2 = (2 x 1.3 x 1024) / 6.02x10^23 = 4.32g

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3 years ago
Will mark the BEST answer as BRANLIEST!
BigorU [14]

Answer:

1. 2Fe + 3CuSO₄ →  Fe₂(SO₄)₃ + 3Cu.

2. Pb(NO₃)₂+ 2Kl →  PbI₂ + 2KNO₃.

3. Mg + 2HCl →  MgCl₂ + H₂.

4. H₂O →  H₂ + 1/2O₂.

5. 2Mg + O₂ → 2MgO.

<h3 /><h2>explanation: 1. Combine iron and copper (II) sulfate solution. (Hint: Iron will form the iron (III) ion)</h2>

2Fe + 3CuSO₄ →  Fe₂(SO₄)₃ + 3Cu.

It is a redox reaction including replacing Cu with Fe and changing their oxidation states.

That Fe replaces Cu and resulting in ferric sulfate.

2. Combine lead (II) nitrate and potassium iodide solutions.

Pb(NO₃)₂+ 2Kl →  PbI₂ + 2KNO₃.

It is a double replacement reaction that lead nitrate reacts with potassium iodide resulting in lead iodide and potassium nitrate.

3. Combine magnesium metal and hydrochloric acid solution.

Mg + 2HCl →  MgCl₂ + H₂.

It is a dissolution reaction that HCl dissolve Mg and resulting in Magnesium chloride and hydrogen gas is evolved.

4. Electrolysis (splitting) of water.  

H₂O →  H₂ + 1/2O₂.

Water electrolysis resulting in splitting of water to produce hydrogen and water.

5. Burning magnesium.

2Mg + O₂ → 2MgO.

It is a combustion reaction that Mg is burned with oxygen to produce magnesium oxide.

Explanation:1. Combine iron and copper (II) sulfate solution. (Hint: Iron will form the iron (III) ion)

2Fe + 3CuSO₄ →  Fe₂(SO₄)₃ + 3Cu.

It is a redox reaction including replacing Cu with Fe and changing their oxidation states.

That Fe replaces Cu and resulting in ferric sulfate.

2. Combine lead (II) nitrate and potassium iodide solutions.

Pb(NO₃)₂+ 2Kl →  PbI₂ + 2KNO₃.

It is a double replacement reaction that lead nitrate reacts with potassium iodide resulting in lead iodide and potassium nitrate.

3. Combine magnesium metal and hydrochloric acid solution.

Mg + 2HCl →  MgCl₂ + H₂.

It is a dissolution reaction that HCl dissolve Mg and resulting in Magnesium chloride and hydrogen gas is evolved.

4. Electrolysis (splitting) of water.  

H₂O →  H₂ + 1/2O₂.

Water electrolysis resulting in splitting of water to produce hydrogen and water.

5. Burning magnesium.

2Mg + O₂ → 2MgO.

It is a combustion reaction that Mg is burned with oxygen to produce magnesium oxide.

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