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Mila [183]
1 year ago
7

In a process called photosynthesis, plants use carbon dioxide and water, along with energy from sunlight, to produce sugar and o

xygen. photosynthesis is represented by the equation what must a plant need to produce 4 molecules of sugar? 6 molecules of co2 6 molecules of h2o 18 molecules of co2 24 molecules of h2o
Chemistry
1 answer:
Alex Ar [27]1 year ago
4 0

24 molecules of H2O are needed by the plant to produce 4 molecules of sugar.

<h2>What is photosynthesis?</h2>

The process by which plants convert carbon dioxide, water, and sunlight into oxygen and sugar-based energy is known as photosynthesis.

<h3>The photosynthesis equation is as follows:</h3>

                   6CO2 + 6H2O + Sunlight → C6H12O6 + 6O2

The following three significant activities are involved in photosynthesis:

1. Chlorophyll absorbs light energy.

2. Water molecules are divided into hydrogen and oxygen and light energy is converted to chemical energy.

3. Carbon dioxide is converted to sugars.

         

Therefore, a plant needs four molecules of H2O and four molecules of CO2 to make one molecule of glucose or sugar, hence a plant needs 24 molecules of H2O and 24 molecules of CO2 to make four molecules of sugar.

Learn more about photosynthesis here:

brainly.com/question/19160081

#SPJ4

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How many grams of oxygen gas occupy 12.3 L of space at 109.4 kPa and 15.4oC?
I am Lyosha [343]

17.93 grams of oxygen gas occupy 12.3L of space at 109.4 kPa and 15.4°C. Details about how to calculate mass can be found below.

<h3>How to calculate mass?</h3>

The mass of a given gas can be calculated by multiplying the number of moles of the substance by its molar mass.

However, the number of moles of the gas must be calculated first as follows:

PV = nRT

Where;

  • P = pressure = 1.0796941atm
  • V = volume = 12.3L
  • n = number of moles
  • T = temperature = 288.4K
  • R = gas law constant = 0.0821 Latm/molK

1.079 × 12.3 = n × 0.0821 × 288.4

13.27 = 23.68n

n = 13.27/23.68

n = 0.56mol

Mass = 0.56 × 32

mass of oxygen gas = 17.93g

Therefore, 17.93 grams of oxygen gas occupy 12.3L of space at 109.4 kPa and 15.4°C.

Learn more about mass at: brainly.com/question/19694949

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