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2 years ago

Chris noticed a high-pressure system in the weather forecast for Monday

Chemistry

1 answer:

Alchen [17]2 years ago

5 0

Answer:

A. Clear and Sunny

Explanation:

The answer would be A. Clear and Sunny. A high pressure system occurs where the air mass above the Earth is denser than in surrounding areas, and therefore exerts a higher force or pressure. They usually happen with li9ght winds. Using process of elimination, it could not be D. Warm and Stormy, C. Cloudy and Rainy, or B. Cold and Stormy because all have wet climates.

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A stock solution is 28.2 percent ammonia (NH3) by mass, and the solution has a density of 0.8990 grams per milliliter. What volu

Savatey [412]

Answer:

$\boxed{\text{20.2 mL}}$

Explanation:

Assume that the volume of the stock solution is 1 L.

1. Mass of stock solution

$\text{Mass} = \text{1000 mL} \times \dfrac{\text{0.8990 g}}{\text{1 mL}} = \text{899.0 g}$

2.Mass of NH₃

$\text{Mass of NH}_{3} = \text{899.0 g stock} \times \dfrac{\text{28.2 g NH}_{3}}{\text{100 g stock}} = \text{253.5 g NH}_{3}$

3. Moles of NH₃

$\text{Moles of NH}_{3} = \text{253.5 g NH}_{3}\times \dfrac{\text{1 mol NH}_{3}}{\text{17.03 g NH}_{3}}= \text{14.89 mol NH}_{3}$

4. Molar concentration of stock solution

$c = \dfrac{\text{moles}}{\text{litres}} = \dfrac{\text{14.89 mol}}{\text{1 L}} = \text{14.89 mol/L}$

5. Volume of stock needed for dilution

Now that you know the concentration of the stock solution, you can use the dilution formula .

$c_{1}V_{1} = c_{2}V_{2}$

to calculate the volume of stock solution.

Data:

c₁ = 14.89 mol·L⁻¹; V₁ = ?

c₂ = 0.500 mol·L⁻¹; V₂ = 600 mL

Calculations:

$\begin{array}{rcl}14.89V_{1} & = & 0.500 \times 600\\14.89V_{1} & = & 300\\V_{1} & = & \text{20.2 mL}\\\end{array}\\\text{You will need $\boxed{\textbf{20.2 mL}}$ of the stock solution.}$

4 0

3 years ago

Monodisperse polyacrylonitrile contains molecules with the general formula -(CH2CHCN)n-, where n is typically greater than 10,00

pentagon [3]

Answer:

7.68 × 10²⁴

Explanation:

Step 1: Calculate the mass of 1 molecule of the monomer CH₂CHCN

We will get the mass of the monomer by adding the masses of the elements.

mCH₂CHCN = 3 × mC + 3 × mH + 1 × mN

mCH₂CHCN = 3 × 12.01 amu + 3 × 1.01 amu + 1 × 14.01 amu = 53.07 amu

Step 2: Convert the mass of the monomer to grams

We will use the conversion factor 1 amu = 1.66 × 10⁻²⁴ g

53.07 amu × 1.66 × 10⁻²⁴ g/1 amu = 8.81 × 10⁻²³ g

Step 3: Calculate "n"

We will divide the mass of the polymer by the mass of the monomer.

n = 676.8 g / 8.81 × 10⁻²³ g = 7.68 × 10²⁴

6 0

3 years ago

An astronaut leaves the International Space Station (ISS) on a tethered line. Although ISS and Earth exert gravitational force o

dexar [7]

Answer: D)The distance from Earth and mass of ISS exert negligible gravitational force on the astronaut.

Explanation:

The distance from Earth and mass of ISS exert negligible gravitational force on the astronaut. Gravity is a very weak force and varies with mass and the inverse square of distance. The astronaut's distance from Earth and the relative small mass of ISS result in gravitational force near zero.

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3 years ago

En el aire, el oxígeno representa el 21%en volumen.

saw5 [17]

Pregunta en guglu ay te ayudara

8 0

3 years ago

Kayla is creating a model to show her understanding of the water cycle. She wants to show that water is constantly cycling betwe

Orlov [11]

Answer:C

Explanation:

It would be the most visually understandable.It would be easyer to understand what you are modeling.

3 0

3 years ago