Answer:
The atomic number of silicon is 14 while atomic mass of carbon is 14.
Explanation:
An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.
All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example if neutral atom has 6 protons than it must have 6 electrons. The sum of neutrons and protons is the mass number of an atom while the number of protons are number of electrons is the atomic number of an atom.
In given atoms ¹⁴₆C and ²⁸₁₄Si the atomic mass of carbon is 14 while the atomic number of silicon is 14. It means silicon has 14 electrons or protons while carbon has 6 protons or electrons because its atomic number is 6. Carbon has 6 protons and 8 neutrons in its nucleus while silicon has 14 protons and 14 neutrons in its nucleus.
In C:
Number of neutrons + protons = 8 + 6 = 14 amu (mass number)
Number of electrons = 6
In Si:
Number of neutrons + protons = 14 + 14 = 28 amu (mass number)
Number of electrons = 14
Answer:
Electronegativity generally increases from left to right across a period,
Explanation:
The true statement from the given choices is that electronegativity generally increases from left to right across a period.
Electronegativity is the measure of the relative tendency with which an atom of the element attract valence electrons in a chemical bond.
Across a period electronegativity increases from left to right and decreases down the group.
This is due to reduction in metallic properties as we move across the period from left to right.
Answer:
I don't <u>understand</u><u> </u><u>your</u><u> </u><u>question</u><u> </u>
Answer:
Explanation:
The two green substances are not the same. Most of their properties are different, except some are alike. Since not all of their properties are matching, they are not the same substance.
I am not sure if this is what you were looking for, but if it is then I am happy to help.