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Lilit [14]
2 years ago
6

Chris noticed a high-pressure system in the weather forecast for Monday

Chemistry
1 answer:
Alchen [17]2 years ago
5 0

Answer:

A. Clear and Sunny

Explanation:

The answer would be A. Clear and Sunny. A high pressure system occurs where the air mass above the Earth is denser than in surrounding areas, and therefore exerts a higher force or pressure. They usually happen with li9ght winds. Using process of elimination, it could not be D. Warm and Stormy, C. Cloudy and Rainy, or B. Cold and Stormy because all have wet climates.

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Two rigid transformations are used to map TriangleJKL to TriangleMNQ. The first is a translation of vertex L to vertex Q. What i
Elodia [21]

Answer:

The second transformation is a rotation around (point) L.

Explanation:

Generally, a rigid transformation is used to change only the position of a figure while the shape remains the same. In order to map a triangle (ΔJKL) to another triangle (ΔMNQ), two rigid transformations were employed. In the first transformation, the vertex L was mapped to the vertex Q. Therefore, the second transformation will definitely involve the rotation around (point) L. This will complete the two rigid transformations.

7 0
3 years ago
Read 2 more answers
This table resembles a condensed version of the modern periodic table. Using the full periodic table as a reference, type the sy
Mekhanik [1.2K]

re write the question.

Explanation:

it seems incomplete.

5 0
2 years ago
I need to balance an equation
mina [271]
I inserted a picture to show u how I worked it out

3 0
3 years ago
Answer the following questions about the fermentation of glucose (C6H12O6, molar mass 180.2 g/mol)
Yuri [45]

The amount of energy in kilocalories released from 49 g of glucose given the data is -4.4 Kcal

How to determine the mole of glucose

Mass of glucose = 49 g

Molar mass of glucose = 180.2 g/mol

Mole of glucose = ?

Mole = mass / molar mass

Mole of glucose = 49 / 180.2

Mole of glucose = 0.272 mole

How to determine the energy released

C₆H₁₂O₆ →2C₂H₆O + 2CO₂  ΔH = -16 kcal/mol

From the balanced equation above,

1 mole of glucose released -16 kcal of energy

Therefore,

0.272 mole of glucose will release = 0.272 × -16 = -4.4 Kcal

Thus, -4.4 Kcal were released from the reaction

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

6 0
1 year ago
The rate constant for the decomposition of n2o is 2.30 s−1. What is the half-life of the decomposition?
Alchen [17]

Answer:

0.3 s.

Explanation:

Half-life of a first order reaction is defined as the the time taken for any fraction of the reaction to complete is independent of the initial concentration.

Half-life of a first order reaction, t° = 0.693/k

where,

t° = half-life of the reaction

k = rate constant

= 2.3 s^-1

Therefore,

t° = 0.693/2.3

= 0.30 s.

3 0
3 years ago
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