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3 years ago

How do the nuclides 16 8o and 15 8o differ?

1 answer:

6 0

The nuclides 16O8 and 15O8 differs in their atomic weight. 16O8 has an atomic weight of 16 amu while 15O8 has an atomic weight of 15 amu. They also differ in the amount of neutrons, 16O8 has 8 protons and 8 neutrons (16 - 8) while 15O8 only has 7 neutrons (15 - 8 protons).

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how many grams of calcium sulfate are produced from 10 grams of calcium nitrate and how many grams of calcium sulfate are produc

AlekseyPX

Answer: 8.30 g of calcium sulfate are produced from 10 grams of lithium sulfate.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} Ca(NO_3)_2=\frac{10g}{164g/mol}=0.061moles$

$\text{Moles of} Li_2SO_4=\frac{10g}{110g/mol}=0.091moles$

$Ca(NO_3)_2+Li_2SO_4\rightarrow 2LiNO_3+CaSO_4$

According to stoichiometry :

1 mole of $Ca(NO_3)_2$ require = 1 mole of $Li_2SO_4$

Thus 0.061 moles of $Ca(NO_3)_2$ will require= $\frac{1}{1}\times 0.061=0.061moles$ of $Li_2SO_4$

Thus $Ca(NO_3)_2$ is the limiting reagent as it limits the formation of product and $Li_2SO_4$ is the excess reagent.

As 1 mole of $Ca(NO_3)_2$ give = 1 mole of $CaSO_4$

Thus 0.061 moles of $Ca(NO_3)_2$ give = $\frac{1}{1}\times 0.061=0.061moles$ of $CaSO_4$

Mass of $CaSO_4=moles\times {\text {Molar mass}}=0.061moles\times 136g/mol=8.30g$

Thus 8.30 g of calcium sulfate are produced from 10 grams of lithium sulfate.

6 0

3 years ago

19. What is sthe mass of 6.02 x 1024 atoms

alekssr [168]

The mass of magnesium in $6.02 \times 10^{24}$ atoms is 240 g.

Answer: Option A

Explanation:

First, we have to convert the atoms to moles of magnesium.

We know that $6.02 \times 10^{24}$ atoms are present in 1 mole of magnesium. So,

$\text { 1 atom }=\frac{1}{6.02 \times 10^{24}} \text { moles }$

$6.02 \times 10^{24} \text { atoms }=\frac{6.02 \times 10^{24}}{6.02 \times 10^{23}} \text { moles }=10 \text { moles }$

Thus,

$Mass of M g= molar mass of M g \times No. of moles of M g$

$\text { Mass of } M g=24 \times 10=240 g$

Thus, 240 g of Magnesium is present in $6.02 \times 10^{24}$ atoms.

4 0

3 years ago

An example of an impermeable material is a. clay. b. sand. c. gravel. d. water.

const2013 [10]

A is the answer to the question you asked.

7 0

3 years ago

Please please please help

weqwewe [10]

Answer:

See explanation.

Explanation:

Hello!

In this case, since the main molecular reaction that is taken place in the beaker is:

$AgNO_3(aq)+BaI_2(aq)\rightarrow AgI(s)+Ba(NO_3)_2(aq)$

In such a way, we understand that one breaker contained silver nitrate and the other one barium iodide. Thus, the complete molecular equations turns out:

$2AgNO_3(aq)+BaI_2(aq)\rightarrow 2AgI(s)+Ba(NO_3)_2(aq)$

Now, for the complete ionic equation, we just ionize the aqueous species:

$2Ag^++2NO_3^-+Ba^{2+}+2I^-\rightarrow 2AgI(s)+Ba^{2+}+2(NO_3)^-$

Finally, for the net ionic equation we cancel out barium and nitrate ions as the spectator one because they are both sides on the equation:

$2Ag^++2I^-\rightarrow 2AgI(s)$

Best regards!

3 0

3 years ago

Which of the following is the largest volume?

Artist 52 [7]

I will use this conversion:

1m = 1000 mm => 1 = 1m / 1000mm

1 m = 100 cm=> 1 = 1m / 100cm

1m = 10 dm=> 1 = 1m / 10 dm

So,

B) 3.8 * 10^7 cm^3 = 3.8 * 10^7 cm^3 * [1m / 100cm]^3 = 38 m^3

C) 3.8 * 10^5 dm^3 * [1m / 10 dm]^3 = 380 m^3

D) 3.8 * 10^8 mm^3 * [1m / 1000 mm]^3 = 0.38 m^3

Now you can compare the four volumes and conclude which is the largest.

Answer: option C) 3.8 * 10^5 dm^3

5 0

3 years ago