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3 years ago

How do the nuclides 16 8o and 15 8o differ?

1 answer:

6 0

The nuclides 16O8 and 15O8 differs in their atomic weight. 16O8 has an atomic weight of 16 amu while 15O8 has an atomic weight of 15 amu. They also differ in the amount of neutrons, 16O8 has 8 protons and 8 neutrons (16 - 8) while 15O8 only has 7 neutrons (15 - 8 protons).

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A compound is formed when 12.2 g Mg combines completely with 5.16 g N. What is the percent composition of this compound? Please

STALIN [3.7K]

3Mg + N₂= Mg₃N₂
n(Mg)=12,2g÷24,4g/mol=0,5mol-limiting reagent
n(N₂)=5,16g÷28g/mol=0,18mol
n(Mg₃N₂):n(Mg)=1:3, n(Mg₃N₂)=0,166mol, m(Mg₃N₂)=0,166·101,2=16,8g.
%(N)= 2·Ar(N)÷Mr(Mg₃N₂) = 2·14÷101,2=27,66%=0,2766
%(Mg) = 3·Ar(Mg)÷Mr(Mg₃N₂)= 3·24,4÷101,2=72,34% or 100% - 27,66%= 72,34%.

4 0

3 years ago

What is the SI unit of mass? Select one: a.Ounce b.Pound c.Gram d.Newton

Varvara68 [4.7K]

the SI unit of mass is kilogram

8 0

3 years ago

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The smallest units of matter that normally CANNOT be broken down are atoms. molecules. cells. phospholipids.

olya-2409 [2.1K]

Answer: atoms

Explanation:

All matter is made up of smaller indivisible particles called atoms. These atoms are the smallest units of matter ACCORDING to the Dalton's Atomic theory.

Molecules are combined atoms, while cells and phospholipids are complex combination of atoms.

Therefore, atoms is the answer

4 0

3 years ago

Write the isotopic symbol for the following (show your work) a) An isotope of iodine whose atoms have 78 neutrons b) An isotope

morpeh [17]

Answer:

For a: The isotopic representation of iodine is $_{53}^{131}\textrm{I}$

For b: The isotopic representation of cesium is $_{55}^{137}\textrm{Cs}$

For c: The isotopic representation of strontium is $_{38}^{52}\textrm{Sr}$

Explanation:

The isotopic representation of an atom is: $_Z^A\textrm{X}$

where,

Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

For a:

We are given:

Number of neutrons = 78

Atomic number of iodine = 53 = Number of protons

Mass number = 53 + 78 = 131

Thus, the isotopic representation of iodine is $_{53}^{131}\textrm{I}$

For b:

We are given:

Number of neutrons = 82

Atomic number of cesium = 55 = Number of protons

Mass number = 55 + 82 = 137

Thus, the isotopic representation of cesium is $_{55}^{137}\textrm{Cs}$

For c:

We are given:

Number of neutrons = 52

Atomic number of strontium = 38 = Number of protons

Mass number = 38 + 52 = 90

Thus, the isotopic representation of strontium is $_{38}^{52}\textrm{Sr}$

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3 years ago

What is the chemical formula of water? O N20 O H20 O NH3 O HO3

svet-max [94.6K]

Answer:

H20

Explanation:

3 0

3 years ago

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