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yarga [219]
3 years ago
6

A mixture of helium, nitrogen and oxygen has a total pressure of 741 mmHg. The partial pressure of helium is 158 mmHg, and the p

artial pressure of nitrogen is 180 mmHg. What is the partial pressure (in mmHg) of oxygen in the mixture?
Chemistry
2 answers:
anygoal [31]3 years ago
6 0

Answer:

403 mmHg

Hope this helped!

LiRa [457]3 years ago
6 0
403 mmHg hoped this helped
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List 5 foods that contain bacteria?
Assoli18 [71]
Yogurt, kefir, kombucha, sauerkraut, pickles, miso, tempeh, kimchi, sourdough bread and some cheeses.
5 0
3 years ago
In 200 g of a concentrated solution of 70.4 wt% nitric acid (r = 1.41 g/mL, FW(HNO3) = 63.01 g/mol), how many grams of water are
mars1129 [50]

Answer:

59.2 grams

Explanation:

We are given that 70.4% of the weight of the total 200 g of the concentration is made up of nitric acid, the remaining information is not required to solve the problem. Since water and nitric acid are the only components of the solution, the total weight of water is given by:

W = 200*(1-0.704)\\W=59.2\ g

There are 59.2 grams of water in this solution.

5 0
3 years ago
The atomic mass of Cu is 63.5. Find its electrochemical equivalent​
FrozenT [24]

Answer:

The electrochemical equivalent of copper, Cu, is 3.29015544 × 10⁻⁷ g/C

Explanation:

The given parameters are;

The element for which the electrochemical equivalent is sought = Copper

The atomic mass of copper = 63.5

The electrochemical equivalent, 'Z', of an element or a substance is the mass, 'm', of the element or substance deposited by one coulomb of electricity, which is equivalent to a 1 ampere current flowing for a period of 1 second

Mathematically, we have;

m = Z·I·t = Z·Q

We have;

Cu²⁺ (aq) + 2·e⁻ → Cu

Therefore, one mole of Cu, is deposited by 2 moles of electrons

The charge carried one mole of electrons = 1 Faraday = 96500 C

∴ The charge carried two moles of electrons, Q = 2 × 96500 C = 193,000 C

Given that the mass of an atom of Cu = 63.5 a.m.u., the mass of one mole of Cu, m = 63.5 g

Z = \dfrac{m}{Q} = \dfrac{63.5 \ g}{193,000 \ C} = 3.29015544 \times 10^{-4} \, g \cdot C^{-1}

∴ Z = 3.29015544 × 10⁻⁴ g/C = 3.29015544 × 10⁻⁷ g/C

The electrochemical equivalent of copper, Cu, is Z = 3.29015544 × 10⁻⁷ g/C

7 0
3 years ago
Convert 1.422g/cm^2 to mg/mm^2
Natalija [7]
The answer is 14.22 mg / (mm^2)
6 0
3 years ago
Which of the following quantum number combinations is not allowed in a ground-state atom?
ollegr [7]
The third option. The angular quantum number (l) can be any integer between 0 and n-1. Therefore, for the third option, l can be 0, 1, 2, 3, or 4—but not 5.
7 0
3 years ago
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