Because the three states are composed by H2O molecules. I<span>f these substances were different they would be composed by different elements. </span>
Answer:
a0=2
a1=3
a2=2
a3=4
Explanation:
The balanced equation for the complete combustion of methane is:
2CH₃OH₍l₎ + 3O₂₍g₎ → 2CO₂ + 4H₂O₍l₎
This way, there is an equal number of atoms of each kind on both reactants side and the products side.
Therefore the coefficients represented by the unknowns are:
a0=2
a1=3
a2=2
a3=4
The above is the equation for the complete combustion of methanol.
Answer:
The element carbon is a part of seawater, the atmosphere, rocks such as limestone and coal, soils, as well as all living things. ... When plants and animals die, their bodies, wood and leaves decays bringing the carbon into the ground. Some is buried and will become fossil fuels in millions and millions of years.
Explanation:
4.14x10^-3 per minute
First, calculate how many atoms of Cu-61 we initially started with by
multiplying the number of moles by Avogadro's number.
7.85x10^-5 * 6.0221409x10^23 = 4.7273806065x10^19
Now calculate how many atoms are left after 90.0 minutes by subtracting the
number of decays (as indicated by the positron emission) from the original
count.
4.7273806065x10^19 - 1.47x10^19 = 3.2573806065x10^19
Determine the percentage of Cu-61 left.
3.2573806065x10^19/4.7273806065x10^19 = 0.6890455577
The formula for decay is:
N = N0 e^(-λt)
where
N = amount left after time t
N0 = amount starting with at time 0
λ = decay constant
t = time
Solving for λ:
N = N0 e^(-λt)
N/N0 = e^(-λt)
ln(N/N0) = -λt
-ln(N/N0)/t = λ
Now substitute the known values and solve:
-ln(N/N0)/t = λ
-ln(0.6890455577)/90m = λ
0.372447889/90m = λ
0.372447889/90m = λ
0.00413830987 1/m = λ
Rounding to 3 significant figures gives 4.14x10^-3 per minute as the decay
constant.