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1 year ago

If 33.9 ml of h3po4 neutralizes 23.4 ml of 2.28 m koh, what is the molarity of the phosphoric acid?

Chemistry

1 answer:

SpyIntel [72]1 year ago

7 0

Answer: 1.57 M

Explanation:

$M_{A}V_{A}=M_{B}V_{B}\\(33.9)M_{A}-=(23.4)(2.28)\\M_{A}=\frac{(23.4)(2.28)}{33.9}=\boxed{1.57 \text{ M}}$

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____Fe2O3 + ___H2O --> ___Fe(OH)3

Novosadov [1.4K]

Answer:

Fe2O3 + __3_H2O --> __2_Fe(OH)3

Explanation:

____Fe2O3 + __3_H2O --> __2_Fe(OH)3

Fe -2 Fe -2

H - 6 H - 6

O - 6 O- 6

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3 years ago

10/24/14

vlabodo [156]

Answer:

d = Hydrogen and oxygen are being formed.

Explanation:

When current is passed through the water electrolysis take place.

Water is splitted into hydrogen and oxygen gas. Because of this formation bubbles are formed.

At cathode:

2H₂O + 2e⁻ → H₂ + 2OH⁻

Cathode is negatively charged and reduction take place on it.

At anode:

4OH⁻ → O₂ + 2H₂O + 4e⁻

Anode is positively charged and oxidation take place on it.

The over all reaction can be written as:

Chemical equation:

2H₂O (electricity) → 2H₂ + O₂

3 0

3 years ago

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Nucleotides, which are the building blocks of nucleic acids, consist of a phosphate group, a nitrogenous base, and a ___________

MrRissso [65]

The answer is B, 5 carbon sugar

6 0

3 years ago

A certain rock contains 71% orthopyroxene, 20% olivine and 8% clinopyroxene. Name this rock and describe it's provenance.

Elanso [62]

Hm maybe Pyroxene rock

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3 years ago

Density of gold is 19.3g/cm^3 what is the density in lbs/in^3 units

Andre45 [30]

The density in lbs/in³ units : 0.697

<h3>Further explanation</h3>

Given

Density of gold is 19.3 g/cm³

Required

Conversion to lbs/in³

Solution

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

Density formula:

$\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}$

Conversion factor

1 g = 0,00220462 lbs

1 cm³ = 0,0610237 in³

So the density :

$\tt 19.3~\dfrac{g}{1~cm^3}\times \dfrac{cm^3}{0.0610237~in^3}\times \dfrac{0.00220462~lbs}{1~g}=0.697~lbs/in^3$

3 0

3 years ago