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Yuliya22 [10]
2 years ago
10

If 33.9 ml of h3po4 neutralizes 23.4 ml of 2.28 m koh, what is the molarity of the phosphoric acid?

Chemistry
1 answer:
SpyIntel [72]2 years ago
7 0

Answer: 1.57 M

Explanation:

M_{A}V_{A}=M_{B}V_{B}\\(33.9)M_{A}-=(23.4)(2.28)\\M_{A}=\frac{(23.4)(2.28)}{33.9}=\boxed{1.57 \text{ M}}

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How many hydrogen atoms are in 5 molecules of isopropyl alcohol
pychu [463]
You have to double them
5 0
3 years ago
A large weather balloon filled with helium has a volume of 7.00 x 102 L at STP. Which expression should be used to find the mass
balandron [24]

Answer:

mass of Helium = mole of Helium x Molarmass of Helium

Explanation:

Mole of Helium = volume of Helium/ 22.4dm^3/mol

                          = 7.00 x 10^2/22.4

                          = 31.25mol

Mass of Helium = mole of Helium x Molarmass of Helium

                           = 31.25mol x 4g/mol

                           = 125g

7 0
3 years ago
A 275 g sample of a metal requires 10.75 kJ to change its temperature from 21.2 oC to its melting temperature, 327.5 oC. What is
Vlada [557]

Answer:

c=0.127\ J/g^{\circ} C

Explanation:

Given that,

Mass of the sample, m = 275 g

It required 10.75 kJ of heat to change its temperature from 21.2 °C to its melting temperature, 327.5 °C.

We need to find the specific heat of the metal. The heat required by a metal sample is given by :

Q=mc\Delta T

c is specific heat of the metal

c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{10.75\times 10^3\ J}{275\times (327.5 -21.2)}\\\\=0.127\ J/g^{\circ} C

So, the specific heat of metal is 0.127\ J/g^{\circ} C.

4 0
2 years ago
5. A standardized mass was known to weigh exactly 5.0000g. It was weighed on a newly
sergey [27]

Answer:

Absolute error = 0.001

% Error = 002 5

Explanation:

The absolute error is the the difference in the measured value and the actual value of a quantity.

Here the actual value is 5.0000 grams

The measured value is 5.001 grams

Absolute error

5.001 - 5.000\\= 0.001

Percent error

= \frac{AE}{AV}

Where AE stands for absolute error and AV stands for absolute value.

= \frac{0.001}{5.000} * 100\\

= 0.02 %

5 0
3 years ago
How many significant digits are in the number 2370.0?
xz_007 [3.2K]

Answer:

2370.0 contains 4 significant digits and Option (c) is correct .

1.20\times 10^{-3}\ contains\ three\ significant\ digit.

Option (b) is correct .

Step-by-step explanation:

Rules for finding significant digit .

1 : Non-zero digits are always significant.

2: Any zeros between two significant digits are significant .

3: Trailing zeros in the decimal number is also significant.

As the number given be 2,370.0.  

= \frac{23700}{10}

Simplify the above

= 2370

Thus by using the rule given above.

2370.0 contains 4 significant digits.

Option (c) is correct .

As the number given be 0.00120 .  

= \frac{120}{100000}

Simplify the above

= \frac{1.20}{1000}

= 1.20\times 10^{-3}

Thus by using the rule given above.

1.20\times 10^{-3}\ contains\ three\ significant\ digit.

Option (b) is correct .

4 0
2 years ago
Read 2 more answers
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