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2 years ago

If 33.9 ml of h3po4 neutralizes 23.4 ml of 2.28 m koh, what is the molarity of the phosphoric acid?

Chemistry

1 answer:

SpyIntel [72]2 years ago

7 0

Answer: 1.57 M

Explanation:

$M_{A}V_{A}=M_{B}V_{B}\\(33.9)M_{A}-=(23.4)(2.28)\\M_{A}=\frac{(23.4)(2.28)}{33.9}=\boxed{1.57 \text{ M}}$

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Which statement compares the attractive forces that hold particles together?

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Answer:

These are examples of INTERmolecular attractions (the other three are examples of INTRAmolecular bonds).

Explanation:

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3 years ago

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Identify the dominant intermolecular attraction in bh3.

k0ka [10]

The molecule BH3 is trigonal planar, with B in the center and H in the three vertices. Ther are no free electrons. All the valence electrons are paired in and forming bonds.

There are four kind of intermolecular attractions: ionic, hydrogen bonds, polar and dispersion forces.

B and H have very similar electronegativities, Boron's electronegativity is 2.0 and Hydrogen's electronegativity is 2.0.

The basis of ionic compounds are ions and the basis of polar compounds are dipoles.

The very similar electronegativities means that B and H will not form either ions or dipoles. So, that discards the possibility of finding ionic or polar interactions.

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When this is the case, the only intermolecular force is dispersion interaction, which present in all molecules.

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3 years ago

The vapor pressure of liquid iodomethane, CH3I, is 40.0 mm Hg at 249 K.A sample of CH3I is placed in a closed, evacuated contain

lora16 [44]

Explanation:

It is given that vapor pressure of liquid iodomethane is 40.0 mm Hg. So, if we calculate the vapor pressure according to the given values and if its value will be greater than the the given vapor pressure of iodomethane then it means that some of the vapors has converted into liquid state.

As the given values are as follows.

$P_{1}$ = 72.0 mm Hg, $T_{1}$ = 404 K

$P_{2}$ = ? , $T_{2}$ = 249 K

As volume is constant so, according to Gay-Lussac's law pressure is directly proportional to temperature.

$P \propto T$ (at constant volume)

or, $\frac{P}{T}$ = k

Therefore, the formula to calculate the value of $P_{2}$ is as follows.

$\frac{P_{1}}{T_{1}}$ = $\frac{P_{2}}{T_{2}}$

$\frac{72.0 mm Hg}{404 K}$ = $\frac{P_{2}}{249 K}$

$P_{2}$ = 44.37 mm Hg

As calculated vapor pressure is more than the given vapor pressure. Hence, the liquid will convert into gas.

As a result, no condensation will occur and only vapors of iodomethane will be present.

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3 years ago

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dimaraw [331]

A and D I’m not sure tho

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3 years ago

Cu(s), CuCl2 (0.50 M) || Ag(s), AgNO3 (0.010 M) 1.

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Answer:

See explaination

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An electrochemical cell is a device capable of either generating electrical energy from chemical reactions or using electrical energy to cause chemical reactions.

See attachment for the step by step solution of the given problem.

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