Answer:
B.change in colour...
I guess that's the answer
A covalent bond is between 2 atoms results in the sharing of electron pairs. B
The reaction for equation is written as follows
2Cs (s) + 2H2O(l) = 2CsOH (aq) + H2 (g)
The mass of cesium is calculated as follows
Find the moles of H2 by use of ideal gas equation that is Pv = nRT
where n is the number of moles
n = PV/RT
P= 48.1 ml in liters = 48.1 /1000= 0.0481 l
T= 19 + 273.15 = 292.15K
P= 768mm hg
R (gas Constant)= 62.364 l.mmhg/k.mol
n= ( 768mmhg x0.0481 L) /( 62.364 L.mm hg/k.mol x 292.15k) = 2.028 x10^-3 moles
by use of mole ratio from reacting equation between Cs to H2 which is 2 :1 the moles of Cs is therefore = ( 2.028 x10^-3) x 2 = 4.05 x10^-3 moles
mass of cs is therefore = moles x molar mass of cs( 132.9g/mol)
=( 4.05 x10^-3)mol x 132.9 g/mol = 0.539 grams
Answer:
Your question is not complete, but use this answer as a guide for your solution.
Question: A chemistry student weighs out 0.112g of acetic acid (HCH₃CO₂) into a 250. mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1600 <em>M</em> NaOH solution. Calculate the volume of solution the student will need to add to reach the equivalence point. Be sure your answer has the correct number of significant digits.
Answer: Volume of NaOH is 11.6 mL
Explanation:
The reaction of acetic acid with NaOH is as follows:
CH3COOH + NaOH -----> CH3COONa + H2O
M1V1 = M2V2
Here M1 V1 are molarity and volume of acetic acid.
M2, V2 are molarity and volume of NaOH.
Number of moles of acetic acid:
0.112 g CH3COOH × (1 mol / 60.05 g) = 0.001865 mol
Molarity = moles of solute / Liters of solution
Molarity = 0.001865 mol / 0.250 L = 0.00746 M
Hence,
M1 = 0.00746 M
V1 = 250 mL
M2 = 0.160 M
V2 = ?
V2 = M1V1 / M2
V2 = 0.00746 M × 250 mL / 0.160 M
V2 = 11.6 mL
Hence the volume of NaOH is 11.6 mL
Answer: The wavelength is and of this radiation
Explanation:
To calculate the wavelength of light, we use the equation:
where,
= wavelength of the light = ?
c = speed of light =
= frequency of light =
Thus wavelength is and of this radiation