To calculate this,
We know that energy is 1 photon
E = hc/wavelenth
wavelength of 10.0 m
Solution:
h = 6.626 x 10^-34 Jsec
C = 2.9979 x 10^8 m/sec
E = 6.626 10^-34 * 2.9979 10^8 / 10 = 1.9864 10^-26J
Then, the number of photons is computed by:
n = 1000 / 1.9864 10^-26 = 5.04 10^28 photons
Answer:
6× 10⁸
Explanation:
We need to find the multiplication of 2 x 10⁴ by 3 x 10⁴.
2 x 10⁴ × 3 x 10⁴
= (3 × 2) x 10⁴ x 10⁴
= 6 x 10⁴ x 10⁴
= 6 × 10⁴⁺⁴
= 6× 10⁸
Hence, the required answer is 6× 10⁸.
Answer:
C. Y & Z
Explanation:
V, W are imaginary metals here because their valence electrons are typically less than 4. X, Y, Z are non-metals and have higher valence electrons. Here, if V or W bind with X, Y, or Z we make ionic bond (because metal + non metal = ionic). But, if X binds with Y or Z or any combinations of any two of the three non-metals results in covalent bond (non metal + non metal = covalent).
Thus, Y and Z make covalent.
99% sure its false
its arranged by atomic number now i believe
