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Hitman42 [59]
3 years ago
5

Nitrogen and hydrogen react to produce ammonia. What mass of ammonia could be produced from 500 grams of nitrogen? Assume that e

nough hydrogen is available for a complete reaction.

Chemistry
1 answer:
OlgaM077 [116]3 years ago
5 0
The answer is 607g. the working is shown above.

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How many joules are required to convert 16.5 g g of ice at 0.0 ∘C ∘ C to liquid water at 32.0 ∘C ∘ C ? The heat of fusion of wat
photoshop1234 [79]

Answer:

5511 J

Explanation:

Applying,

Q = Cm.................... Equation 1

Where Q = amount of heat required to convert ice, C = Heat of fusion of water, m = mass of ice

From the question,

Given: C = 334 J/g, m = 16.5 g

Substitute these values into equation 2

Q = 334(16.5)

Q = 5511 J

Hence, the amount of heat required is 5511 J

4 0
3 years ago
T-Butyl alcohol was produced by the liquid-phase hydration (using water, W) of isobutene (I) over an Amberlyst-15 catalyst.
Minchanka [31]

Answer:

True

Explanation:

This is because, The hydroboration oxidation of an alkene which is isobutene in the presence of a catalyst will result to alcohol as the product . Therefore, the OH group will attach or link itself to the carbon which is less obstructed. Thus this reaction is in accordance to Anti-Markownikoff's rule.

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8 0
3 years ago
Please helpppp
notka56 [123]
1.

2.Unconformity

3. Folding

4. Law of superposition
4 0
3 years ago
Give an example of an element that would be expected to share similar chemical properties with beryllium, calcium, and strontium
Aleks04 [339]
Strontium possibly but I’m not 100% sure
4 0
4 years ago
Select the correct answer.
kifflom [539]

Answer:

At a given temperature, a system of particles can be considered as point masses (m) each moving at a certain translational velocity (v). The motion of these particles can be defined in terms of their average translational kinetic energy which is responsible for the heat transfer during molecular collisions and therefore the temperature of the system.

The kinetic temperature T is given in terms of the average translational kinetic energy as:

T  = 2/3k(Kinetic energy)

T = 2/3k(1/2*m*v²)

where K = Boltzmann constant

Ans: C) Average translational kinetic energy

7 0
3 years ago
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