The wire is

Mathematics

1 answer:

Mnenie [13.5K]2 years ago

4 0

Step-by-step explanation:

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Q.1 Simplify :- (i) (- 625 ) + 925 + 100 + (-200)

Dmitrij [34]

825 - 625i

Hope it’s right
Best luck with your studying

3 0

3 years ago

Michelle is building a rectangular landing strip for airplanes .She has material to cover 1/1,500 of a square mile. The landing

ANEK [815]

I think that the missing word here is:
"with the amount of the material that Michelle has"

Let's say that her landing strip is x miles long, then its area would be:

$\frac{1}{6} *x$

We also know how big it is:

$\frac{1}{6} *x= \frac{1}{1 500}$

now, let's multiply both sides by 6:
$\frac{6}{6} *x= \frac{6}{1 500}$
$1 *x= \frac{3}{750}$
$x= \frac{1}{250}$

So the answer is that it would be $x= \frac{1}{250}$ miles wide

3 0

4 years ago

Inessa [10]

Answer:

Approximately 920.324 p/m

Step-by-step explanation:

so to figure this out, we need to simply divide 6,688 people by 7.267 square miles. 6,688/7.267=920.324.... So we have approximately 920.324 people per square mile

5 0

3 years ago

Average precipitation for the first 7 months of the year, the average precipitation in toledo, ohio, is 19.32 inches. if the ave

Colt1911 [192]

Part A:

The probability that a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

$P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\sigma}\right)$

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that a randomly selected year will have precipitation greater than 18 inches for the first 7 months is given by:

$P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{2.44}\right) \\ \\ =1-P(z\ \textless \ -0.5410) \\ \\ =1-0.29426=\bold{0.7057}$

Part B:

The probability that an n randomly selected samples of a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

$P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\frac{\sigma}{\sqrt{n}}}\right)$

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that 5 randomly selected years will have precipitation greater than 18 inches for the first 7 months is given by:

 $P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{\frac{2.44}{\sqrt{5}}}\right) \\ \\ =1-P(z\ \textless \ -1.210) \\ \\ =1-0.1132=\bold{0.8868}$

7 0

3 years ago

HELP MEEE! I NEED IT RIGHT NOW!

Daniel [21]

Answer:1/16 for each of us

Step-by-step explanation:

Since only 1/4 is left and you and the teachers are splitting it up,you’d get 1/16 each because the half of 1/4 (1/8) was split into 2 (1/16)

4 0

3 years ago