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777dan777 [17]
2 years ago
14

Determine the points of intersection of the line y=2x+5 and the circle x²+y²=36

Mathematics
1 answer:
Vladimir79 [104]2 years ago
5 0

The two intersection points are (-2.79,  -0.58) and (0.79,  6.58).

<h3>How to find the points of intersection?</h3>

Here we want to solve the system of equations:

y = 2x + 5

x² + y² = 36

To solve this, we need to replace the first equation into the second one:

x² + (2x + 5)² = 36

Now we can solve this for x:

x² + 4x² + 10x + 25 = 36

5x² + 10x - 11 = 0

This is a quadratic equation, to solve it we use the general formula:

x = \frac{-10 \pm \sqrt{10^2 - 4*5*(-11)} }{2*5} \\\\x = \frac{-10 \pm 17.9 }{10}

So we have two solutions for x:

x = (-10 - 17.9)/10 = -2.79

x = (-10 + 17.9)/10 = 0.79

To get the y-values of the solutions, we evaluate the linear equation in these values of x:

y = 2*(-2.79) + 5 = -0.58

y = 2*( 0.79) + 5 = 6.58

Then the two intersection points are (-2.79,  -0.58) and (0.79,  6.58).

If you want to learn more about intersection points:

brainly.com/question/17206319

#SPJ1

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a. \boxed{y-602=\frac{2}{3}(x-3)}

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<h2>Explanation:</h2>

<h3>PART A.</h3>

In this exercise we have that in July Ariel recorded the height of a pine tree and how quickly it was expected to grow in next several months. From the Table, we can get the following points:

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y-y_{1}=m(x-x_{1}) \\ \\ Where: \\ \\ m:Slope \\ \\ (x_{1}, y_{1}):A \ point \ on \ the \ line

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(x_{1}, y_{1}) \rightarrow (3,602) \\ \\ \boxed{y-602=\frac{2}{3}(x-3)}

<h3>PART B.</h3>

In this case, we have that:

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<h3>PART C.</h3>

The y-intercept can be found setting x=0. So, from our equation:

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<h2>Learn more:</h2>

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