M₁ *V₁ = M₂ * V₂
12.0 * V₁ = 6.0 * 500.0
12.0 V₁ = 3000
V₁ = 3000 / 12.0
V₁ = 250 mL
hope this helps!
Answer:
If the volume of a gas increased from 2 to 6 L while the temperature was held constant, <u><em>the pressure of the gas decreased by a factor of 3.</em></u>
Explanation:
Boyle's law that says "The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure." This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.
Boyle's law is expressed mathematically as:
Pressure * Volume = constant
or
P * V = k
To obtain the proportionality factor k you must make the quotient:

k= 3
This means that <u><em>if the volume of a gas increased from 2 to 6 L while the temperature was held constant, the pressure of the gas decreased by a factor of 3.</em></u>
Answer:
290.32 g
Explanation:
First we <u>calculate the volume</u> of the cube:
- Volume = (3.20 cm)³ = 32.768 cm³
Now we <u>convert cubic centimeters to mililiters</u>:
- 32.768 cm³ * 1 mL / 1 cm³ = 32.768 mL
Finally we <u>calculate the mass</u>, using the <em>equation for density</em>:
- mass = 8.86 g/mL * 32.768 mL = 290.32 g