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3 years ago

5. The image above represents a cell going

Chemistry

1 answer:

Amanda [17]3 years ago

6 0

Answer:

The correct answer is option A, that is, mitosis only has one cell division set.

Explanation:

The two kinds of nuclear division that takes place at the time of cell differentiation are meiosis and mitosis. In the process of mitosis, the cells of the body get divide, while in meiosis the sex cells are differentiated.

While going through the process of mitosis, the cell divides only one time, on the other hand, during meiosis a cell divides two times. After going through mitosis production of two diploid daughter cells takes place, while after going through meiosis generation of four haploid daughter cells takes place. Thus, it is clear from the diagram that the process of meiosis is taking place, as the formation of four haploid cells is taking place as the cell is dividing two times.

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MAXImum [283]

Answer:

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Explanation:

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3 years ago

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What are the 3 types of zeros?

kotegsom [21]

Leading zeros
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3 years ago

Which of these is an example of a chemical change?

Elena-2011 [213]

Answer:

D. Burning a peice of wood

Explanation:

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Hope this helps you :)

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3 years ago

Ammonia (NH3) reacts with sulfuric acid to form ammonium sulfate. How many grams of ammonium sulfate are obtained from 8.73 g of

Gwar [14]

I hope you understand my working:
1) Finding the mol of NH3 to find the mol of (NH4)2SO4 (ammonium sulfate)
2) Mr of (NH4)2SO4
3) Theoretical yield: The actual grams of (NH4)2SO4 produced when reacting 0.514 mol of NH3 to 0.514 mol H2SO4
4) Using formula of (given grams)/(theoretical grams or actual grams) * 100 = 73%
5) Basic algebra

4 0

3 years ago

1. Magnesium chloride solution reacts with silver nitrate solution to form magnesium nitrate

Whitepunk [10]

a. 1,4332 g

b. 7.54~g

<h3>Further explanation</h3>

Given

Reaction

MgCl2 (s) + 2 AgNO3 (aq) → Mg(NO3)2 (aq) + 2 AgCl (s)

20 cm of 2.5 mol/dm^3 of MgCl2

20 cm of 2.5 g/dm^3 of MgCl2

Required

the mass of silver chloride - AgCl

Solution

a. mol MgCl2 :

$\tt 20~cm^3=20\times 10^{-3}~dm^3\\\\mol=M\times V\\\\mol=2.5~mol/dm^3\times 20\times 10^{-3}DM^3=0.05$

From equation, mol AgCl = 2 x mol MgCl2=2 x 0.05=0.1

mass AgCl(MW=143,32 g/mol)= 0.1 x 143,32=1,4332 g

b. mol MgCl2 (MW=95.211 /mol):

$\tt mol=M\times V\\\\mol=\dfrac{2.5~g/dm^3}{95,211 g/mol}=0.0263~mol/dm^3$

From equation, mol AgCl = 2 x mol MgCl2=2 x 0.0263=0.0526

mass AgCl(MW=143,32 g/mol)= 0.0526 x 143,32=7.54~g

6 0

3 years ago