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Reptile [31]
2 years ago
5

Describe a situation in which friction changes the direction of a moving object.​

Physics
2 answers:
Zarrin [17]2 years ago
8 0

Answer:

A  car making  a turn

Explanation:

lora16 [44]2 years ago
3 0

Consider a person trying to push a large crate across a floor, as in the diagram. As they apply a force to push the crate along the floor in one direction, a frictional force is generated in the opposite direction.

study \: well.....

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dangina [55]
<span>Frequency of a sound wave is called the pitch. Higher frequencies have a higher pitch and lower frequencies have the opposite. When an ambulance travels by a listener, the frequencies are oscillating rapidly and causing the shrill, loud sounds that emanate from the sirens.</span>
6 0
4 years ago
A hockey puck moving at 28 m/s is caught by an 80,00 kg man who was at
zimovet [89]

Answer:

A

Explanation:

all the work is in the attached file :D

8 0
4 years ago
Refer to the image. Calculate the magnitude of change in velocity of the cue ball.
valkas [14]

Answer:

If you add the 2 velocity vectors you get the velocity of the third vector which is the (change in) velocity of the cue ball after striking the cushion

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6 0
2 years ago
At one point in the circuit, there is an LED and a resistor in parallel with one another. If you measure the voltage drop across
kifflom [539]

Answer:

C. The voltage drop across the resistor is 2.1V and nothing about the current through the resistor.

Explanation:

When connected in parallel, voltage across the resistances are the same. So if 2.1V was dropped across the LED then 2.1V was also dropped across the resistor. However, this tells us nothing about the current through the resistor. We can find the current across the resistor if we know the resistance of the resistor, but that's about it.

If it were a series connection, then the current would have been the same, but the voltage drop were another story.

7 0
3 years ago
A box took 5 minutes to move you did 2150 j of work in the process. how much power was required to move the box
AURORKA [14]
Power = Work/Time

Convert 5 min to seconds and divide 2150J by that number.
4 0
3 years ago
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