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lorasvet [3.4K]
3 years ago
12

Sulphuric acid production equations​

Chemistry
1 answer:
earnstyle [38]3 years ago
3 0

Answer:

H2SO4

Explanation:

Physical properties: H2SO4 is a colorless or slightly yellow viscous liquid with a pungent odor. It has a density of 1.84 g/mL, boiling point of 337 °C, and melting point of 10 °C. "Concentrated" sulfuric acid is 98% in water, and is the most stable form.

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MgSO4 x 7H2O:
natka813 [3]

Answer:In regards to writing the formula, we know that magnesium has a charge of 1+ and sulfate, SO4, has a charge of 1-. Sulfate is a polyatomic ion so the charge of the whole thing is (SO4)1-. When you combine them you end up with MgSO4 and the "heptahydrate" is seven water molecules.

Explanation:

5 0
3 years ago
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Which of the following is the energy of moving electrons?
mezya [45]

Answer:

Electrical energy

Explanation:

Electrical energy is caused by the moving of electrons.

hope it helps!

6 0
3 years ago
Which of the following is the composition of an isotope of calcium (atomic number 20)?
ivolga24 [154]

20 protons

20 electrons ( as much elctrons as protons because there has to be same positive and negative to have a neutral atom)

And the number of neutrons depends of the mass number but in that case, I think that it's a Calcium atom (Ca) and so there are 20 netrons.

5 0
3 years ago
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A flask holds 3.01 x 10^23 molecules of carbon dioxide. The container is holding
Andrew [12]
B) 0.50 moles of carbon dioxide.

4 0
4 years ago
How many photons are produced in a laser pulse of 0.897 J at 407 nm?
Leona [35]
The relationship between energy of a single photon and its wavelength can be determined using the formula E=hc/lambda where E is energy, h is Planck's constant, c is the speed of light, and lambda is photons.

Before being able to solve for energy, need to convert nanometers to meters.

407 nm (1 m/1 x 10^9 nm) = 4.07 x 10^-7 m

Then plug in the values we know into the equation.
E h(Planck's constant) c(speed of light)
E = (6.63 x 10^-34 Js)(3 x 10^8 m/s) / 4.07 x 10^-7 m (lambda)

E=(0.000000000000000000000000000000000663js)(300,000,000m/s)=1.989×10^-25j/ms

E=1.989x10^-25j/ms /{divided by} 4.07x10^-7m = 4.8869779x10^-33 J (the meters cancel out)

E = 4.89 x 10^-33 J

This gives us the energy in Joules of a single photon. Now, we can find the number of photons in 0.897 J

0.897J / 4.89 x 10^-33 J = ((0.897 J) / 4.89) x ((10^(-33)) J) = 1.8343558 x 10^-34

1.83435583 × 10-34m4 kg2 / s4 photons
4 0
4 years ago
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