Answer:
93.50±5%
Explanation:
Hello,
The average of the results turns out in 93.50% Na2CO3, thus, the range that the true value lies on is:
93.50±5%
For us to have be 95% confident that we've got the correct result.
Best regards.
It's what you put :)
ΔH is the distance from the reactants (which would be E), to the products (which would be G or D)
Find the number of moles
C = n / V
C(Concentration) = 0.30 moles / L
V ( Volume) = 2 L
n = ??
n = C * V
n = 0.30 mol / L * 2 L
n = 0.60 mol
Find the molar mass
2Na = 23 * 2 = 46 grams
1S = 32 * 1 = 32 grams
O4 = 16 * 4 = 64 grams
Total = 142 grams / mol
Find the mass
n = given mass / molar mass
n = 0.06 mol
molar Mass = 142 grams / mol
given mass = ???
given mass = molar mass * mols
given mass = 142 * 0.6
given mass = 85.2 grams.
85.2 are in a 2 L solution that has a concentration of 0.6 mol/L
6.32 KJ is how much heat is given off
Answer:
e. Dilute a solution of commercial vinegar to prepare it for titration.
a. Perform a scout colorimetric titration of diluted vinegar with NaOH.
b. One pair performs a careful colorimetric titration of diluted vinegar with NaOH and the other pair performs a potentiometric titration of diluted vinegar with NaOH.
c. Perform a scout colorimetric titration of HCL with NaOH.
d. One pair performs a careful colorimetric titration of HCL with NaOH and the other pair performs a potentiometric titration of HCL with NaOH.
Explanation:
Titration is a process in which acid and base are introduced together to determine unknown concentration of acid or base. This is also known as neutralization reaction. The chemical process form salt and water as by products because acid molecules react with base molecules.