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2 years ago

If you compare the mass of a

Chemistry

1 answer:

Varvara68 [4.7K]2 years ago

4 0

Answer:

the answer is (B)

the mass before equals the mass after

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How do you use nonmetal in a sentence?

skad [1K]

Here Is A Sentence You Could Possibly Use:

"Hydrogen and Nitrogen are two examples of non-metals."

(You can replace the two given elements with whatever two non-metallic elements you like.)

Hope This Helps!

BTW, You May Want A Second Opinion Just In Case! :)

7 0

3 years ago

i like this guy but i don't think he likes me back. he also goes to school somewhere else, but we see eachother every friday. he

Firdavs [7]

You should try to strt a conversation with him or say hi introduce yourself or ask him how hes doing just talk to him i guess

3 0

4 years ago

Read 2 more answers

What volume of 1.10 M SrCl2 is needed to prepare 525 mL of 5.00 mM SrCl2?

grigory [225]

Answer:- 2.39 mL are required.

Solution:- It's a dilution problem and to solve this type of problems we use the dilution equation:

$M_1V_1=M_2V_2$

Where, $M_1$ and $M_2$ are molarities of concentrated and diluted solutions and $V_1$ and $V_2$ are their respective volumes.

$M_1$ = 1.10M

$M_2$ = 5.00mM = 0.005M (since, mM stands for milli molar and M stands for molar. 1M = 1000mM)

$V_1$ = ?

$V_2$ = 525 mL

Let's plug in the given values in the formula:

$1.10M(V_1)=0.005M(525mL)$

$V_1=(\frac{0.005M*525mL}{1.10M})$

$V_1=2.39mL$

So, 2.39 mL of 1.10M are needed to make 525 mL of 5.00mM solution.

7 0

3 years ago

How much energy does an X-ray with an 8 nm (8 x 10-9 m) wavelength have?

Vlada [557]

Answer: 2.48×10^-17 J

Explanation:

Given the following :

Wavelength = 8nm (8 x 10^-9 m)

Energy(e) of X-ray =?

Energy=[speed of light(c) × planck's constant (h)] ÷ wavelength

Speed of light = 3×10^8m/s

Planck's constant = 6.626×10^-34 Js

Wavelength = 8 x 10^-9 m

Energy = [(3×10^8) * (6.626×10^-34)] / 8 x 10^-9

Energy = [19.878×10^(8-34)] / 8 x 10^-9

Energy = 2.48475 × 10^(-26+9)

Energy = 2.48×10^-17 J

8 0

3 years ago

Convert the composition of the following alloy from atom percent to weight percent (a) 44.9 at% of silver, (b) 46.3 at% of gold,

vesna_86 [32]

Answer:

Mass percentage of gold : 33.35%

Mass percentage of silver: 62.80%

Mass percentage of copper : 3.85%

Explanation:

$N=n\times N_A$

Where : N = Number of atoms

n = moles

$N_A=6.022\times 10^{23}$ = Avogadro number

Let the total atoms present in the alloy be 100.

Atom percentage of silver = 44.9%

Atoms of of silver = 44.9% of 100 atoms = 44.9

Atomic weight of silver = 107.87 g/mol

Mass of 44.9 silver atoms = 107.87 g/mol × 44.9 = 4,843.363 g/mol

Atom percentage of gold= 46.3%

Atoms of of gold = 46.3% of 100 atoms = 46.3

Atomic weight of gold = 196.97 g/mol

Mass of 44.9 gold atoms = 196.97 g/mol × 46.3 = 9,119.711 g/mol

Atom percentage of copper = 8.8 %

Atoms of of copper = 8.8% of 100 atoms = 8.8

Atomic weight of copper = 63.55 g/mol

Mass of 44.9 copper atoms = 63.55 g/mol × 8.8 = 559.24 g/mol

Total mass of an alloy :4,843.363 g/mol + 9,119.711 g/mol + 559.24 g/mol

Mass percentage of gold :

$\frac{4,843.363 g/mol}{4,843.363 g/mol + 9,119.711 g/mol + 559.24 g/mol}\times 100=33.35 \%$

Mass percentage of silver:

$\frac{9,119.711 g/mol}{4,843.363 g/mol + 9,119.711 g/mol + 559.24 g/mol}\times 100=62.80\%$

Mass percentage of copper :

$\frac{559.24 g/mol}{4,843.363 g/mol + 9,119.711 g/mol + 559.24 g/mol}\times 100=3.85\%$

7 0

3 years ago