![\tt -\dfrac{1}{2}\dfrac{d[N_2O]}{dt}=\dfrac{1}{2}\dfrac{d[N_2]}{dt}=\dfrac{1}{1}\dfrac{d[O_2]}{dt}](https://tex.z-dn.net/?f=%5Ctt%20-%5Cdfrac%7B1%7D%7B2%7D%5Cdfrac%7Bd%5BN_2O%5D%7D%7Bdt%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5Cdfrac%7Bd%5BN_2%5D%7D%7Bdt%7D%3D%5Cdfrac%7B1%7D%7B1%7D%5Cdfrac%7Bd%5BO_2%5D%7D%7Bdt%7D)
<h3>Further explanation</h3>
Reaction
2N2O(g) — 2N2(g) + O2(g)
Required
relative rate
Solution
The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.
so the relative rates for the reaction above are :
Answer:
2Cl- ⇒ Cl ↓2+ 2e
Explanation: sorry if this is not what you were looking for.
The efficiency of any machine is given by:
efficiency = output obtained / input given
Substituting the values,
Efficiency = 105 / 150
Efficiency = 0.7
Converting this to a percentage, the efficiency of the hammer is 70%.
This is a fairly high efficiency, and this is due to the fact that the hammer is a simpler machine. The more complex a machine is, the greater are the losses in it due to friction, meaning there is a lower efficiency.
Answer:
acids or bases can be tested
by chemical indicators
