Answer:
the energy vacancies for formation in silver is 
Explanation:
Given that:
the equilibrium number of vacancies at 800 °C
i.e T = 800°C is 3.6 x 10¹⁷ cm3
Atomic weight of sliver = 107.9 g/mol
Density of silver = 9.5 g/cm³
Let's first determine the number of atoms in silver
Let silver be represented by N
SO;
where ;
avogadro's number = 
= Density of silver = 9.5 g/cm³
= Atomic weight of sliver = 107.9 g/mol
N = 5.30 × 10²⁸ atoms/m³
However;
The equation for equilibrium number of vacancies can be represented by the equation:
From above; Considering the natural logarithm on both sides; we have:
Making 
the subject of the formula; we have:
where;
K = Boltzmann constant = 8.62 × 10⁻⁵ eV/atom .K
Temperature T = 800 °C = (800+ 273) K = 1073 K
Where;
1 eV = 1.602176565 × 10⁻¹⁹ J
Then
Thus, the energy vacancies for formation in silver is
ANSWERS:
Group 2 metal carbonates, nitrates and hydroxides decompose to heat to give the corresponding metal oxide and release CO2, NO2 and O2, and H2O respectively. The thermal stability increases down the group as theionic character of the compounds increases down the group.
Answer:
Solids can hold their shape because their molecules are tightly packed together. ... Atoms and molecules in liquids and gases are bouncing and floating around, free to move where they want. The molecules in a solid are stuck in a specific structure or arrangement of atoms.
<em>Hope it helps...</em>
Answer:
2,3–dimethylpentane
Explanation:
To know which option is correct, we shall determine the name of the compound.
To obtain the name of the compound, do the following:
1. Determine the longest continuous carbon chain. This gives the parent name of the compound.
2. Identify the substituent group attached to the compound.
3. Locate the position of the substituent group by giving it the lowest possible count.
4. Combine the above to obtain the name of the compound.
Now, we shall determine the name of the compound as follow:
1. The longest continuous carbon chain is 5. Thus, the parent name of the compound is pentane.
2. The substituent group attached is methyl (–CH₃)
3. There are two methyl group attached to the compound. One is located at carbon 2 and the other at carbon 3.
4. Therefore, the name of the compound is:
2,3–dimethylpentane
None of the options are correct.
