The pH of the solution of the given acid is 3.099
Let HX be the weak acid:
HX ⇌
+ 
For which:
= [
][
] / [HX]
If
lies in the range
we can assume that the equilibrium concentrations used in the expression are a good enough approximation to the initial concentrations.
Rearranging and taking negative logs of both sides gives:
pH = ![\frac{1}{2} [pK_{a} - loga]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5BpK_%7Ba%7D%20-%20loga%5D)
a is the concentration of the acid.
= -log (2×
) = 5.69
pH = ![\frac{1}{2} [5.69- (-0.508)]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5B5.69-%20%28-0.508%29%5D)
pH = 3.099
Learn more about pH of acid here;
brainly.com/question/13043236
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Answer:
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Explanation:
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Answer:
262.8 g
Explanation:
Molarity = 3.0M
Mass = ?
Volume = 2.40L
The relationship between these quantities is given as;
Molarity = Number of moles / Volume
Number of moles = Molarity * Volume
Number of moles = 3 * 2.4 = 7.2 mol
Mass = Number of moles * Molar mass
Molar mass of HCl = 1 + 35.5 = 36.5 g/mol
Mass = 7.2 * 36.5 = 262.8 g
Answer:
1. D/E
2. D/J
3. B/F
4. D or G/I
5. A
Explanation:
This is about sort of concentrations:
1- Molarity
Moles of solute in 1 L of solution
(we can also say, mmoles of solute in 1 mL)
2- Molality
Moles of solute in 1kg of solvent
3. mass %
grams of solute in 100g of solution
4. mole fraction
moles of solute or solvent per moles of solution
5. ppm
mg of solute in 1kg of solution
(we can also say μg of solute in 1 g of solution, or mg solute in 1L of solution)