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2 years ago

Which two reactants make Calcium carbonate?

Chemistry

2 answers:

Norma-Jean [14]2 years ago

3 0

Impossible to form from given reactants

Explanation:

Only sodium has carbonate ion here .so only possible way to displace carbonate is to use potassium

When sodium carbonate and Potassium iodide react with each other double displacement reaction occurs

As potassium is powerful than sodium it displaces sodium to form potassium carbonate .

Then you have to use water and then you can use calcium suppliment .

Debora [2.8K]2 years ago

3 0

Answer:

Calcium chloride
Sodium carbonate

Explanation:

The reaction :

CaCl₂ + Na₂CO₃ ⇒ CaCO₃ + 2NaCl

This is clearly an example of a displacement reaction, where sodium displaces calcium in calcium chloride to form sodium chloride, and we are left with calcium carbonate.

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What does conserving mass mean in a chemical equation?

Keith_Richards [23]

The answer would be C. Hope this helps

4 0

3 years ago

Read 2 more answers

Nitrogen dioxide is produced by combustion in an automobile engine. For the following reaction, 0.377 moles of nitrogen monoxide

Contact [7]

Answer:

The amount of NO₂ that can be produced 8.533 g

Explanation:

According to question

2 NO(g) + O₂(g) → 2 NO₂(g)

Given

Moles of nitrogen monoxide = 0.377

Moles of oxygen = 0.278

$'For NO'=\frac{Mole}{Stoichiometry}=\frac{0.377}{2} =0.1855\\'For O_{2} '=\frac{0.278}{1}= 0.278\\$

Since 'NO' is the limiting reagent according to this ratio.

According to equation

2 moles NO reacts to form 2 moles NO₂

So, 0.1855 moles NO give = 0.1855 moles of NO₂

Mass of 1 mole NO₂ = 46 g/mole

Mass of 0.1855 moles = 46 x 0.1855 = 8.533 g

5 0

4 years ago

After reading the list of physical properties above, you realize that they are describing a substance that is a

Alecsey [184]

The answer is B

Hope this helps!

5 0

3 years ago

Determine the number of grams of Carbon in 215 g of sucrose.

olya-2409 [2.1K]

just find the percent mass of oxygen in sucrose again. and then multiply that by 50.00.

6 0

4 years ago

An aqueous CsCl solution is 8.00 wt% CsCl and has a density of 1.0643 g/mL at 20°C. What is the boiling point of this solution?

umka2103 [35]

Answer: The boiling point of solution is 100.53

Explanation:

We are given:

8.00 wt % of CsCl

This means that 8.00 grams of CsCl is present in 100 grams of solution

Mass of solvent = (100 - 8) g = 92 grams

The equation used to calculate elevation in boiling point follows:

$\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}$

To calculate the elevation in boiling point, we use the equation:

$\Delta T_b=iK_bm$

Or,

$\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

Boiling point of pure solution = 100°C

i = Vant hoff factor = 2 (For CsCl)

$K_b$ = molal boiling point elevation constant = 0.51°C/m

$m_{solute}$ = Given mass of solute (CsCl) = 8.00 g

$M_{solute}$ = Molar mass of solute (CsCl) = 168.4 g/mol

$W_{solvent}$ = Mass of solvent (water) = 92 g

Putting values in above equation, we get:

$\text{Boiling point of solution}-100=2\times 0.51^oC/m\times \frac{8.00\times 1000}{168.4g/mol\times 92}\\\\\text{Boiling point of solution}=100.53^oC$

Hence, the boiling point of solution is 100.53

6 0

3 years ago