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3 years ago

5

Members at a yoda school pay $11 per class plus a one-time $96 membership fee. Non members pay $14 per class. How many classes w

ould a member have to take to save money compared to taking classes as a non-member?

1 answer:

kirill [66]3 years ago

6 0

The difference in pay per class is 3, so to even out with he 96, you’d have to take 32 classes, the profit begins at the 33rd
Hope this helps

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Which of the following is a solution of x2 + 2x + 8?

zubka84 [21]

Using the quadratic equation we get:
$\frac{ - 2 + - \sqrt{4 - 32} }{2} = \frac{ - 2 + - \sqrt{ - 28} }{2}$

Factoring out 2 we get
$\frac{ - 2 + - 2\sqrt{ - 7} }{2} = - 1( + - ) \sqrt{ - 7}$
Factoring out the imaginary number:
$- 1 + \sqrt{7} i \: (and) \: - 1 - \sqrt{7} i$
So b.

4 0

3 years ago

Plzzz help its really easy , im just really du mb

alina1380 [7]

Answer:

36.8/2.8 = 16

Expression 1 = 368/28

Expression 2 = 3.68/.28

Step-by-step explanation:

If you move the decimal the same on both numbers of a division problem the answer stays the same.

5 0

3 years ago

Read 2 more answers

find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B

SashulF [63]

Answer:

$\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190$

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately $\theta \approx 48$

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

$a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10$

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

$|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3$

$|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5$

And finally we can calculate the angle between the vectors like this:

$cos \theta = \frac{ab}{|a| |b|}$

And the angle is given by:

$\theta = cos^{-1} (\frac{ab}{|a| |b|})$

If we replace we got:

$\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190$

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately $\theta \approx 48$

3 0

3 years ago

CAN SOMEONE PLZ HELP

dybincka [34]

It would be C. 7*7*7*7*7

Hope this helps

Have a great day/night

8 0

3 years ago

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Find the value for x. Round your answer to the nearest hundredth. Area of the triangle = 8 ft^2

zmey [24]

Answer:

x = 3.51

Step-by-step explanation:

Since, formula to determine the area f a triangle is,

Area = $\frac{1}{2}(\text{Base})(\text{Height})$

8 = $\frac{1}{2}(x + 1)(3x - 7)$

16 = x(3x - 7) + 1(3x - 7)

16 = 3x² - 7x + 3x - 7

16 = 3x² - 4x - 7

0 = 3x² - 4x - 23

3x²- 4x - 23 = 0

By quadratic formula,

x = $\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$

x = $\frac{4\pm \sqrt{(-4)^{2}-4(3)(-23)}}{2(3)}$

x = $\frac{4\pm \sqrt{292}}{6}$

x = $\frac{4\pm 17.09}{6}$

x = 3.51, -2.18

But the length of sides can't be negative.

Therefore, x = 3.51 will be the answer.

8 0

3 years ago