Answer:
student ticket = $11
(adult ticket = $15)
Step-by-step explanation:
Let a = price of adult ticket
Let s = price of student ticket
Given:
- On the first night she sold 12 adult tickets and 11 student tickets for $301 dollars
⇒ 12a + 11s = 301
Given:
- On the second night she made $134 selling 6 adult tickets and 4 student tickets
⇒ 6a + 4s = 134
Multiply 6a + 4s + 134 by 2 then subtract from 12a + 11s = 301 to eliminate a:
⇒ (6a + 4s = 134) × 2: 12a + 8s = 268
12a + 11s = 301
- (12a + 8s = 268)
--------------------------
3s = 33
⇒ s = 33 ÷ 3 = 11
Substitute found value of s into one of the equations and solve for a:
⇒ 12a + 11(11) = 301
⇒ 12a + 121 = 301
⇒ 12a = 180
⇒ a = 15
Therefore, the price of an adult ticket is $15 and the price of a student ticket is $11
Answer: C. 254
Step-by-step explanation: All engineers is the population so this is stats and the number that chose math no matter what kind of engineer is 254
Answer:
Figure M
Step-by-step explanation:
Figure P has vertices at points (-2,4), (-2,8), (-6,8) and (-6,6).
Consider figure M with vertices (-4,-4), (-4,-8), (-8,-8) and (-8,-6).
1. Translate figure M 2 units to the right. This translation has the rule:
(x,y)→(x+2,y),
so
- (-4,-4)→(-2,-4);
- (-4,-8)→(-2,-8);
- (-8,-8)→(-6,-8);
- (-8,-6)→(-6,-6).
2. Reflect the translation image figure M across the x-axis according to the rule
(x,y)→(x,-y)
Thus,
- (-2,-4)→(-2,4);
- (-2,-8)→(-2,8);
- (-6,-8)→(-6,8);
- (-6,-6)→(-6,6).
Answer:
The input of a algebraic equation
Step-by-step explanation:
You're welcome
