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netineya [11]
2 years ago
8

2069 (Set B) Q. No. 9d How much force is required to punch a hole 1 cm in diameter in a steel sheet 5mm thick whose shearing str

ength is 2.76 × 108 Nm 2. X [4]​
Physics
1 answer:
Pavlova-9 [17]2 years ago
3 0

The force required to punch a hole 1 cm in diameter in a steel sheet is 0.176 x 10¹³ N.

<h3>What is force?</h3>

The force is defined as the shear stress or pressure applied per unit area.

F = P/A

Given is a steel sheet whose thickness t = 5mm = 5x 10⁻³ m, shearing strength P = 2.76 × 10⁸ N/m², diameter of hole d = 1cm = 1x 10⁻² m

The area to be punched A = πd xt

A = π x 1x 10⁻² x5x 10⁻³

A = 15.7 x 10⁻⁵ m²

The force required to punch a hole is

F = 2.76 × 10⁸ /  15.7 x 10⁻⁵

F = 0.176 x 10¹³ N.

Thus, the punching force is  0.176 x 10¹³ N.

Learn more about force.

brainly.com/question/21763500

#SPJ1

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