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laila [671]
3 years ago
14

Give an example of how a bicycle rider would accelerate? Explain the three different ways a bicyclist could

Physics
1 answer:
Ostrovityanka [42]3 years ago
7 0

A cyclist can increase the speed of their bike in various ways such as, changing gears, positioning themselves properly, increase the pedalling rate

<h3>Ways in which a cyclist can increase the speed of a bicycle</h3>

Bicycle riders could accelerate/ increase their speed in various ways

  • By Changing the gears and by doing so increasing the speed
  • By Positioning themselves in a streamlined manner, this is so that they become aerodynamic hence they cut across airflow.
  • By increase the rate at which they are pedalling the bicycle.

Learn more about increasing bicycle speed here:

brainly.com/question/13749553

You might be interested in
How to calculate? I got 15000N for (a)
MAXImum [283]
Your answer for part a is correct.  Using Newton's 3rd Law, the force on the rocket by the exhaust leaving the rocket is the same magnitude (opposite direction) as the downward force applied to the exhaust.
In part b the net force is the upward force from the exhaust thrust minus the downward force of gravity:

F_{net}=F_{thrust}-mg=15,000N-1500kg \times 1.6 \frac{m}{s^2}=12,600N

Then using the Second Law, we get for part c:

F=ma \\ a= \frac{F}{m} = \frac{12600N}{1500kg} =8.4 \frac{m}{s^2}

The force and acceleration are in the upward direction
3 0
3 years ago
A meter stick on earth made from a uniform-density material rests on a fulcrum positioned precisely at its middle. If a box of m
Nadusha1986 [10]

Answer:

A force of 75 N placed at 0.7 m on the meter stick.

Explanation:

The weight of the box is equal to:

W=mg=3*10=30N

The net torque is equal to zero and is equal to:

F(x-0.5)-(30*0.5)=0\\F(x-0.5)=15

For a force with a value of 75 N that is placed at 0.70 m on the meter stick, it would produce a torque of 15 N m

If you replace that values in the equation:

75(0.7-0.5)=15\\15=15

8 0
4 years ago
Which biome's yearly rainfall mainly evaporates?
tino4ka555 [31]
India's monsoon area i beleive
7 0
4 years ago
Read 2 more answers
Encuentra en forma gráfica el peso de un objeto que se encuentra suspendido del techo por 2 cuerdas, las cuales ejercen una fuer
cestrela7 [59]

Answer:

709.06 N

Explanation:

To do this, you need to do the drawing of this exercise. In the picture below, you have the draw, and the procedure to do this exercise. You need to apply 2nd Newton's law which is:

F = m*a

However, in this case, we only have tension and the weight of the object (As you can see in the picture), and we have no movement, the object it's supposed to be in rest, so, second law becomes this:

F = 0

In this case, we have rod and weight so the forces involving here are those, so second law is like this:

T1y + T2y - W = 0

To get the T1y and T2y, we have the angle so:

T1y = 320 sin80° = 315.14 N

T2y = 400 sin80° = 393.92 N

With these values, replace them and we get:

315.14 + 392.92 - W = 0

709.06 - W = 0

W = 709.06 N

5 0
3 years ago
A plane is flying east when it drops some supplies to a designated target below. The supplies land after falling for 10 seconds.
Ivanshal [37]

Part 1)

here we know that supply took 10 s to reach the ground

so here we will have

y = \frac{1}{2}gt^2

y = \frac{1}{2}\times 9.8 \times 10^2

y = \frac{1}{2}\times 9.8 \times 100

y = 490 m

Part 2)

Here all the supply covered horizontal distance of 650 m in 10 s interval of time

so here we can say

speed = \frac{distance}{time}

v = \frac{650}{10}

v = 65 m/s


4 0
3 years ago
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