For the hypothetical reaction A → B, calculate the average rate of disappearance of A if the initial concentration of A is 0.91
1 answer:
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Hi there!
We must begin by converting km/h to m/s using dimensional analysis:
Now, we can use the kinematic equation below to find the required acceleration:
vf² = vi² + 2ad
We can assume the object starts from rest, so:
vf² = 2ad
(17.22)²/(2 · 75) = a
a = 1.978 m/s²
Now, we can begin looking at forces.
For an object moving down a ramp experiencing friction and an applied force, we have the forces:
Fκ = μMgcosθ = Force due to kinetic friction
Mgsinθ = Force due to gravity
A = Applied Force
We can write out the summation. Let down the incline be positive.
ΣF = A + Mgsinθ - μMgcosθ
Or:
ma = A + Mgsinθ - μMgcosθ
We can plug in the given values:
22(1.978) = A + 22(9.8sin(5)) - 0.10(22 · 9.8cos(5))
A = 46.203 N
Answer:
For a gas held at constant temperature, we can apply Boyle's law, which states that the product between the gas pressure and its volume is constant:
where
P is the pressure
V is the volume
As we see from the equation, P and V are inversely proportional to each other: this means that when the volume is decreased, the pressure increases, and vice-versa. The reason for that is that when the volume is decreased, the gas is compressed, so the molecules of the gas come closer to each other, so they collide more frequently with the wall of the container, exerting therefore a greater pressure.