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3 years ago

11

For the hypothetical reaction A → B, calculate the average rate of disappearance of A if the initial concentration of A is 0.91

M and the concentration of A after 90 minutes is 0.11 M.

1 answer:

marishachu [46]3 years ago

7 0

Answer:

The right answer is 8.9 x 10^-3 M/min

Explanation:

A → B

-d [A]/dt = K [A]

ΔA/Δt = - (C2 -C1)/t2 - t1

= - (0.11 - 0.91)/90

= 8.9 x 10^-3 M/min

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A basketball has a coefficient of restitution of 0.821 in collisions with the wood floor of a basketball court. The ball is drop

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Answer: The height of its fourth bounce = 0.43m

Explanation:

The coefficient of restitution denoted by (e), is the ratio that shows the final velocity to initial relative velocity between two objects after collision

IT is given by the formula in terms of height as

Coefficient of Restitution, e = √(2gh))/√(2gH) = √(h/H)

Where

Coefficient of Restitution, e= 0.821

H = 2.07 m

At fourth bounce , we have that

Coefficient of Restitution, e⁴ =√(h₄/H)

Putting the given values and solving , we have,

e⁴ =√(h₄/H)

= 0.821⁴ = √(h₄/2.07)

(0.821⁴ )² =h₄/2.07

0.2064 x 2.07 = 0.427 = 0.43

At fourth bounce, h₄ height = 0.43m

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adell [148]

Answer:

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Explanation:

Given that,

Mass of a ship roller coaster is 36,000 kg.

It reaches a height of 20 m off the ground

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E = mgh

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E = 36,000 kg × 9.8 m/s² × 20 m

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or

E = 7056 kJ

So, it will have 7056 kJ of gravitational potential energy.

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Where $n =$ number of charges means in our case number of electrons

$n = \frac{It}{e}$

$n = \frac{1 \times 10^{5} }{1.6 \times 10^{-19} }$

$n = 6.25 \times 10^{23}$

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