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Dima020 [189]
3 years ago
11

For the hypothetical reaction A → B, calculate the average rate of disappearance of A if the initial concentration of A is 0.91

M and the concentration of A after 90 minutes is 0.11 M.
Physics
1 answer:
marishachu [46]3 years ago
7 0

Answer:

The right answer is 8.9 x 10^-3 M/min

Explanation:

           A → B

-d [A]/dt  = K [A]

ΔA/Δt     = - (C2 -C1)/t2 - t1

               = - (0.11 - 0.91)/90

               = 8.9 x 10^-3 M/min

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sveticcg [70]
Gravitational potential energy is the higher it us above the ground the more gravitational potential energy it holds.Sphere 2 says it has three times the mass of sphere 1. Therefore the answer is Sphere 2 since it was raised three time the mass of sphere 1. and the rest of the answer choices dont make sense.
5 0
2 years ago
An object is thrown horizontally off a cliff with an initial velocity of 5.0 meters per second. The object strikes the ground 3.
vladimir2022 [97]

The acceleration of gravity is 9.8 m/s².  This simply means that when anything falls, its downward speed keeps increasing, and it falls 9.8 m/s faster every second than it fell 1 second earlier.

After 3 seconds of falling, the object is falling at (3 x 9.8 m/s) = 29.4 m/s faster than at the beginning of the 3 seconds.  If it had no vertical speed at the beginning of the 3 seconds, then THAT's its speed after 3 seconds . . . . . <em>29.4 m/s</em> downward.

As far as being thrown horizontally off the cliff . . . that has no effect on it vertical speed.  Horizontally, it doesn't matter whether it rolls gently over the edge, or somebody throws it horizontally, or it gets shot horizontally out of a high power rifle.  It hits the ground at the same time and with the same speed in every case.

6 0
4 years ago
Read 2 more answers
Determine the rate at which the electric field changes between the round plates of a capacitor, 5.8 cm in diameter, if the plate
Natalka [10]

Answer:

The rate at which the electric field changes between the round plates of a capacitor is 125\times 10^{3}Vs^{-1}.

Explanation:

It is given in the problem that the round plates of a capacitor are spaced some distance apart and the voltage across them is changing.

The expression for the electric field in terms of voltage is as follows;

E=\frac{V}{d}

Here, E is the electric field, V is the voltage and d is the distance of separation.

Differentiate expression of the electric field with respect to time, t.

\frac{dE}{dt}=\frac{1}{d}\frac{dV}{dt}

Convert the distance of separation from mm to m.

d= 1.2 mm

d=1.2\times 10^{-3}m

Calculate the rate at which the electric field changes.

\frac{dE}{dt}=\frac{1}{d}\frac{dV}{dt}

Put \frac{dV}{dt}=150 Vs^{-1} and d=1.2\times 10^{-3}m

\frac{dE}{dt}=\frac{1}{1.2\times 10^{-3}}(150)

\frac{dE}{dt}=125\times 10^{3}Vs^{-1}

Therefore, the rate at which the electric field changes is 125\times 10^{3}Vs^{-1}.

4 0
3 years ago
A steel piano string of mass per unit lenght 4×10-⁴kgm-¹ was struck, if the speed of the sound on the string is 300ms-¹. Calcula
drek231 [11]

Answer:

36 N

Explanation:

Velocity of a standing wave in a stretched string is:

v = √(T/ρ),

where T is the tension and ρ is the mass per unit length.

300 m/s = √(T / 4×10⁻⁴ kg/m)

T = 36 N

4 0
4 years ago
A horse gallops a distance of 10 kilometers in a time of 30 minutes its average speed is?
Gennadij [26K]

Answer:

20 km/hr

Explanation:

Distance = 10km

Time = 30 minutes = 1/2 hour

Average Speed = Total distance / Total Time Taken

                           = 10 ÷  1/2

                           = 10 x 2

                           = 20 km/hr

3 0
3 years ago
Read 2 more answers
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