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Vedmedyk [2.9K]
1 year ago
9

One Affective way to develop the feeling function in one’s personality is to

Physics
1 answer:
Mademuasel [1]1 year ago
5 0

Answer:

A.

Explanation:

I think it’s a. Because, I normally think about how someone else feels if I want to say something.

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Why would scientists use a hand lens to observe minerals?
charle [14.2K]

Explanation:

C.To measure the length and width of the mineral

6 0
2 years ago
What is the acceleration of a sinking rock if it has a mass of 0.25 kg and has a net force of 0.44 N acting on it?
charle [14.2K]

Answer: 1.76 m/s²

Explanation:

F = mass x acceleration

0.44 N = (0.25)(a)

0.44/0.25 = 1.76

a = 1.76

3 0
3 years ago
Two people, one of mass 85 kg and the other of mass 50 kg, sit in a rowboat of mass 90 kg. With the boat initially at rest, the
sergeinik [125]

Answer:

0.11m

Explanation:

let's assume the boat is of uniform construction

Ignoring friction losses

Also assume the origin is at the end of the boat originally with the heavier person

the center of mass of the whole system will not change relative to the water when the two swap ends

Originally, the center of mass is

85[0] + 90[3.5/2] + 50[3.5] / (85 + 90 + 50) = 1.14m from the origin

after the swap, the center of mass is

50[0] + 90[3.5/2] + 85[3.5] / (85 + 90+ 50) = 1.030m from the origin

The center of mass has shifted

1.14-1.030 = 0.11m

as no external force acted on the system, the center of mass relative to the water will not change. The boat will therefore shift towards the end where the heavier person originally sat

4 0
3 years ago
Determine the gravitational field 300km above the surface of the earth. How does this compare to the field on the earth's surfac
Serjik [45]
The strength of the gravitational field is given by:
g= \frac{GM}{r^2}
where
G is the gravitational constant
M is the Earth's mass
r is the distance measured from the centre of the planet.

In our problem, we are located at 300 km above the surface. Since the Earth radius is R=6370 km, the distance from the Earth's center is:
r=R+h=6370 km+300 km=6670 km= 6.67 \cdot 10^{6} m

And now we can use the previous equation to calculate the field strength at that altitude:
g= \frac{GM}{r^2}= \frac{(6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2})(5.97 \cdot 10^{24} kg)}{(6.67 \cdot 10^6 m)^2}  = 8.95 m/s^2

And we can see this value is a bit less than the gravitational strength at the surface, which is g_s = 9.81 m/s^2.
4 0
3 years ago
Which of the following statements describes the movement of air?
Nutka1998 [239]
The movement of air flows from high pressure to low pressure
3 0
3 years ago
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