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Makovka662 [10]
3 years ago
14

Determine the gravitational field 300km above the surface of the earth. How does this compare to the field on the earth's surfac

e?
Physics
1 answer:
Serjik [45]3 years ago
4 0
The strength of the gravitational field is given by:
g= \frac{GM}{r^2}
where
G is the gravitational constant
M is the Earth's mass
r is the distance measured from the centre of the planet.

In our problem, we are located at 300 km above the surface. Since the Earth radius is R=6370 km, the distance from the Earth's center is:
r=R+h=6370 km+300 km=6670 km= 6.67 \cdot 10^{6} m

And now we can use the previous equation to calculate the field strength at that altitude:
g= \frac{GM}{r^2}= \frac{(6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2})(5.97 \cdot 10^{24} kg)}{(6.67 \cdot 10^6 m)^2}  = 8.95 m/s^2

And we can see this value is a bit less than the gravitational strength at the surface, which is g_s = 9.81 m/s^2.
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3. Carbohydrates. Examples as starch and glycogen

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3 years ago
A 0.46-kg cord is stretched between two supports, 7.2 m apart. When one support is struck by a hammer, a transverse wave travels
Kryger [21]

Answer:

      T = 6.0 N

Explanation:

given,

mass of the cord = 0.46 Kg

length of the supports = 7.2 m

time taken to travel = 0.74 s

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using formula for tension calculation

T = \dfrac{v^2.m}{l}

v = \dfrac{l}{s}

v = \dfrac{7.2}{0.74}

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The tension in the cord is equal to 6.0 N.

7 0
3 years ago
What are the 3 Newton's law of motions?
irinina [24]

Answer:

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4 0
2 years ago
You throw a glob of putty straight up toward the ceiling, which is 3.60 m above the point where the putty leaves your hand. The
Sliva [168]

Answer:

Explanation:

Given

Height of ceiling is h=3.6\ m

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Speed of Putty just before it strike the ceiling is given by

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v^2=19.69

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v=u+at

4.43=9.5-9.8\times t

t=\frac{5.07}{9.8}

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3 years ago
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